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FranLet's denote the two consecutive numbers as x and x+1. The square of the first number is x^2, and the square of the second number is (x+1)^2. The difference between their squares is ((x+1)^2) - (x^2) = 25. Expanding and simplifying this equation gives us x^2 + 2x + 1 - x^2 = 25. Solving for x, we get x = 12. Therefore, the two consecutive numbers are 12 and 13.
Oh, dude, you're hitting me with some math vibes here! So, let's break it down - if we have two consecutive numbers, let's call them x and x+1, their squares would be x^2 and (x+1)^2. Now, the difference between these squares is 25, so we can set up the equation x^2 - (x+1)^2 = 25 and solve for x. So, the two consecutive numbers would be 3 and 4. Math, man, it's wild!
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