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write an algebraic expression for 4 more than p
When two dies are rolled, there are 36 different outcomes. (1,1),(1,2),....(6,6). Let A denote the event of rolling doubles. There are 6 doubles (1,1),(2,2),(3,3),(4,4),(5,5),(6,6) P(A) = 6/36=1/6 Let B denote the event that the product is 18. Count how many of these outcomes give you a product of 18. Only (3,6) and (6,3) give you a product of 18. P(B)=2/36=1/18 There are no events that give you a double and whose product is 18. P(A or B) = P(A)+P(B) P( double or 18) = 1/6+1/18 = 4/18 = 2/9
If a divides b and b divides a then either a is equal to b or a is equal to -b. Additional note: if a divides b, there exist a p such that ap=b. and if b divides a, there exist a q such that a=bq. then ap=(bq)p=b => b(1-pq)=0 => pq=1 since b!=0 => p=q=1 or p=q=-1 => a=b or a=-b
6*abs(b - p) which can also be written as 6*|b - p|