1st = The quadratic term.
2nd = The linear term.
3rd = The constant term.
A quadratic sequence is when the difference between two terms changes each step. To find the formula for a quadratic sequence, one must first find the difference between the consecutive terms. Then a second difference must be found by finding the difference between the first consecutive differences.
Oh, dude, it's like this: all quadratic equations are polynomials, but not all polynomials are quadratic equations. A quadratic equation is a specific type of polynomial that has a degree of 2, meaning it has a highest power of x^2. So, like, all squares are rectangles, but not all rectangles are squares, you know what I mean?
Let's denote the two numbers as x and y. We know that x - y = 4 and xy = 60. From the first equation, we can express y in terms of x as y = x - 4. Substituting this into the second equation gives x(x - 4) = 60. Solving this quadratic equation yields x = 10 and y = 6. So, the two numbers are 10 and 6.
To find the pattern in the sequence 3, 11, 21, 33, 47, 63, we first need to calculate the differences between consecutive terms: 8, 10, 12, 14, 16. We notice that the differences are increasing by 2 each time. This indicates a quadratic relationship. By finding the second differences (which are constant at 2), we can conclude that the sequence follows a quadratic equation of the form an^2 + bn + c. Therefore, the nth term for this sequence is given by the quadratic equation an^2 + bn + c, where a = 1, b = 2, and c = 0.
25+11=36: Let f and s represent the first and second numbers respectively. The statement of the problem yields two equations: f + s =36 and f = 3 + 2s. Substituting the function given in the second equation for f into the first equation yields 3 + 2s + s = 36, or (subtracting 3 from each side and merging the s terms, 3s = 33 or s = 11. Then f + 11 = 36 (substituting the value for s into the first equation), or f = 25.
Of or pertaining to a square, or to squares; resembling a quadrate, or square; square., Tetragonal., Pertaining to terms of the second degree; as, a quadratic equation, in which the highest power of the unknown quantity is a square.
Without an equality sign and no square variable the given terms can not be that of a quadratic equation.
One of its terms will be squared and it will have two solutions.
Because solutions of quadratic equation depend solely on these three constants.
Eliminate the fraction by multiplying all the terms by the denominator.
A quadratic sequence is when the difference between two terms changes each step. To find the formula for a quadratic sequence, one must first find the difference between the consecutive terms. Then a second difference must be found by finding the difference between the first consecutive differences.
Without an equality sign the given terms can't be considered to be a quadratic equation.
Translate to what? I assume you need help interpreting it. The quadratic equation is used to solve the quadratic polynomial, ax2 + bx + c = 0, where a, b, and c can be any number. For example, if you need to solve the equation x2 = 5 + 2x, you first convert it into the standard form mentioned above: x2 - 2x - 5 = 0. Now find the coefficients, a, b, and c. In this case, a = 1, b = -2, c = -5. Finally, you replace these coefficients in the quadratic equation. The "plus-minus" sign simply means that the quadratic equation is a shortcut for two equations - one in which you add, the other in which you subtract, the terms at the top. The solutions given by the quadratic equation are values of "x" that satisfy the equation.
is a quadratic equation for y, in terms of x.
Without an equality sign the given terms can't be considered to be any kind of an equation whatsoever..
Presumably this is a quadratic equation in the form of -8k2-12+92 = 0 which will have two solutions. First divide all terms by -4 to bring the equation at its lowest terms remembering that a - divided into a - is equal to a + 2k2+3k-23 = 0 Use the quadratic equation formula to factorise the equation: (2k-5.446221994)(k+4.223110997) = 0 Therefore the solutions are: k = 2.723110997 or k = -4.223110997 to nine decimal places respectively.
In terms of a single variable, say "y", you can only have terms in y2, y and constants. So z-4 + 3z-2 + 5 = 0 can therefore be considered a quadratic equation for z-2, because you can substitute it by y. All other forms that do not follow this pattern are not quadratics.