To find the pattern in the sequence 3, 11, 21, 33, 47, 63, we first need to calculate the differences between consecutive terms: 8, 10, 12, 14, 16. We notice that the differences are increasing by 2 each time. This indicates a quadratic relationship. By finding the second differences (which are constant at 2), we can conclude that the sequence follows a quadratic equation of the form an^2 + bn + c. Therefore, the nth term for this sequence is given by the quadratic equation an^2 + bn + c, where a = 1, b = 2, and c = 0.
the anser is that you are stupid
A single number, such as 1521273339 does not define a sequence. There is no nth term for a signle number.
There are infinitely many possible answers. But the simplest is Un = 33 - 3n for n = 1, 2, 3, ...
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
The 'n'th term is [ 13 + 5n ].
81
the anser is that you are stupid
A single number, such as 1521273339 does not define a sequence. There is no nth term for a signle number.
28
It is increasing by 4 and the nth term is 4n+1
44
33
There are infinitely many possible answers. But the simplest is Un = 33 - 3n for n = 1, 2, 3, ...
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
The 'n'th term is [ 13 + 5n ].
The 'n'th term is [ 13 + 5n ].
It is: 10n-7 and so the next term is 43