To find the pattern in the sequence 3, 11, 21, 33, 47, 63, we first need to calculate the differences between consecutive terms: 8, 10, 12, 14, 16. We notice that the differences are increasing by 2 each time. This indicates a quadratic relationship. By finding the second differences (which are constant at 2), we can conclude that the sequence follows a quadratic equation of the form an^2 + bn + c. Therefore, the nth term for this sequence is given by the quadratic equation an^2 + bn + c, where a = 1, b = 2, and c = 0.
the anser is that you are stupid
A single number, such as 1521273339 does not define a sequence. There is no nth term for a signle number.
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
I can tell you that it is increasing 9, 15, 21, 27. i.e. adding on 6 to the gap each time so if you mean the next term by nth term, then it will be adding on 33, which will leave you at 113
There are infinitely many possible answers. But the simplest is Un = 33 - 3n for n = 1, 2, 3, ...
81
the anser is that you are stupid
A single number, such as 1521273339 does not define a sequence. There is no nth term for a signle number.
28
It is increasing by 4 and the nth term is 4n+1
44
Here are the first five terms of a sequence. 12 19 26 33 40 Find an expression for the nth term of this sequence.
33
I can tell you that it is increasing 9, 15, 21, 27. i.e. adding on 6 to the gap each time so if you mean the next term by nth term, then it will be adding on 33, which will leave you at 113
There are infinitely many possible answers. But the simplest is Un = 33 - 3n for n = 1, 2, 3, ...
The first differences are 5, 7, 9, 11, 13 and the second differences are 2,2,2,2 so the formula for the nth term is a quadratic. tn = n2 + 2n - 2 (n = 1,2,3,...)
The 'n'th term is [ 13 + 5n ].