If you mean: 2n = 5-2 then n = 1.5
If you mean: 4n-2n = 4 then 2n = 4 and n = 2
Every number multiplied by 2 is an even number, so that 2n is an even number. Usually we represent an even number by 2n.
It is a linear expression in two variables.
If you mean: 4n = 1-23-2n then 6n = -22 and so n = 11/3
2N Refers to a diploid cell or organism, in which two copies of each gene are present. Cells before and after mitosis are 2N, or diploid. Cells before meiosis are 2n, and following meiosis are 1n, or haploid.
2n + 4m - 2n + m = 5m
14-2n = 12
n to n
DDR1 has a prefetch of 2n, which means it can store 2 bits of data in each prefetch buffer.
You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
I am assuming that 2n is an algebraic expression, and n is limited to positive integer values. The first 4 multiples of 2n are 0 (2n*0), 2n (2n*1), 4n (2n*2), and 6n (2n*3). If you are looking for non-0 multiples, you would also include 8n (2n*4).