They are numbers of the form 2n and 2n+2 where n is any integer.
150, 152, 154Let the three consecutive even numbers be 2n-2, 2n & 2n+2, then:(2n-2) + 2n + (2n+2) = 456⇒ 6n = 456⇒ n = 76Which means the three numbers are:2n-2 = 2 x 76 - 2 = 1502n = 2 x 76 = 1522n+2 = 2 x 76 + 2 = 154
Let 2n be the first integer, then the next on is 2n+2 and the one after is 2n+4 so adding all three we have 6n+6=108 or 6n=102 and we want 2n so divide we divide 6n by 3 and we have 2n=34, and 2n+2=36 and lastly 2n+4=38 so 34, 36, 38 are the even integers we seek.
Two odd numbers added together will always be an even number. I'll show how: Let M and N be any two integers. 2M is even, and 2N is even. So (2M +1) is an odd number, and (2N + 1) is an odd number. (2M +1) + (2N +1) = 2M + 1 + 2N +1 = 2M + 2N + 2 = 2(M + N + 1), which is even.
Answer116, 118, 120, 122, 124Procedureassume the numbers are such that the middle one is 2n,the assumed numbers are: 2n-4, 2n-2, 2n, 2n+2, 2n+4 ..... (1)Summation = 10n = 600so, n = 60Substitute with n = 60 in (1) we get the answer above
Every number multiplied by 2 is an even number, so that 2n is an even number. Usually we represent an even number by 2n.
2n+2n equals 4n
2n + 2 = 2(n+1)
odd x even = even (2n + 1)(2n) = 2[n(2n + 1)] let n(2n + 1) = t = 2t (even)
Let's take a look at this. For any integer n, 2n always be even, then the next consecutive number 2n + 1 must be odd. Let add them first, 2n + 2n + 1 = 4n + 1 = 2(2n) + 1 So their sum is odd, since every even number multiplied by 2 is also even. Let's multiplied them, 2n(2n + 1) = (2n)^2 + 2n Their product is even, since every even number raised in the second power is also even, and the sum of two even numbers is even too. So the answer is that when the sum of two numbers can be odd, their product is an even number. (note that the sum of two odd numbers is even)
It is the nth even number.
In general mathematicians use n to signify any integer. On this basis 2n must be an even integer.But, are you sure it was a mathematician who wrote 2n ? There's no law about this.
Any even number can be written in the form 2n for some natural number n.Any odd number can be written as 2n+1 for a natural number nNow add an even to an odd.2n+2n+1=4n+1 which is 2(2n)+1 and this is the form for an odd number.
If you mean: 2n = 5-2 then n = 1.5
Answerno solutionProcedureAssume the numbers are:2n, 2n+2, 2n+4, 2n+6, 2n+8, 2n+10Summation = 12n + 30 = 60012n = 597n = not integer numberno solution
They are numbers of the form 2n and 2n+2 where n is any integer.
If you mean: 4n-2n = 4 then 2n = 4 and n = 2