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it means combinatorial or combination, you use the formula nCr = n!/((n-r)! x r!). example 5c3 = 5! / ((5-3)! x 3!) = 5! / (2! x 3!) = (5x4x3x2x1) / ((2x1) x (3x2x1)) = 10
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There are two sections in a question paper each contain five questions A students has to answer 6 questions?
he can choose the answer in this way, 5c1*5c3+5c2*5c2+5c3*5c1 evaluate, the answer will be 200.
How many sums of money can be formed from 5 coins if exactly 3 coins are used?
Only one, if all five coins have the same value. Otherwise, 5C3= 10 is the maximum number.Only one, if all five coins have the same value. Otherwise, 5C3= 10 is the maximum number.Only one, if all five coins have the same value. Otherwise, 5C3= 10 is the maximum number.Only one, if all five coins have the same value. Otherwise, 5C3= 10 is the maximum number.
How many combinations of three can you make with 5 choices?
5C3 = 10
How many 3 item combinations are there if you have 5 items?
There are 5C3 = 10 combinations.
How many groups of three can you make out of 5 flowers?
There are 5C3 = 10 groups.
How many combinations of 3 books out of 5?
There are 5C3 = 5*4/(2*1) = 10 combinations
How Many Combination of three coins can you make from five coins?
There are 5C3 = (5*4*3)/(2*1) = 30 combinations.
How many different groups of 3 letters can you make from A B C D and E?
There are 5C3 = 5*4/(2*1) = 10 groups.
In the city of x the probabilty of rain is 50 percent What is the probabilty that it will rain 3 out of 5 days?
It is 5C3*(1/2)3*(1/2)2 = 10/32 = 5/16
How many three digit number can be formed from 4 5 6 7 8?
One example! 4 × 5 × 6 × 7 − 9 = 831 -------- I disagree with this answer. Three digits can be chosen from five in 5C3 = 10 ways For each of these choices the three digits can be ordered in 6 ways. Therefore, 10(6) = 60 numbers can be formed.
How many arrangements can be made out of the letters of the word mother taken four at a time so that each arrangement contains the letter'm'?
It is 1*5C3*(4*3*2*1) = 240
The probability Mary will receive an A in a class is 0.61 Assuming independence if she is taking 5 classes this semester calculate the probability she will receive exactly 3 As?
P(3a) = 5c3 ∙(0.61)3∙(0.39)2 = 0.3452... ~ 34.5%
