he can choose the answer in this way, 5c1*5c3+5c2*5c2+5c3*5c1 evaluate, the answer will be 200.
Only one, if all five coins have the same value. Otherwise, 5C3= 10 is the maximum number.Only one, if all five coins have the same value. Otherwise, 5C3= 10 is the maximum number.Only one, if all five coins have the same value. Otherwise, 5C3= 10 is the maximum number.Only one, if all five coins have the same value. Otherwise, 5C3= 10 is the maximum number.
5C3 = 10
There are 5C3 = 10 combinations.
There are 5C3 = 10 groups.
There are 5C3 = 5*4/(2*1) = 10 combinations
There are 5C3 = (5*4*3)/(2*1) = 30 combinations.
There are 5C3 = 5*4/(2*1) = 10 groups.
It is 5C3*(1/2)3*(1/2)2 = 10/32 = 5/16
One example! 4 × 5 × 6 × 7 − 9 = 831 -------- I disagree with this answer. Three digits can be chosen from five in 5C3 = 10 ways For each of these choices the three digits can be ordered in 6 ways. Therefore, 10(6) = 60 numbers can be formed.
It is 1*5C3*(4*3*2*1) = 240
P(3a) = 5c3 ∙(0.61)3∙(0.39)2 = 0.3452... ~ 34.5%