10.
There are 120 permutations and 5 combinations.
3 x 5 = 15
There are 1140 5 digit combinations from 1 to 20. 20 combination 3 computes that.
3!(factorial) or six
There are 5C3 = 10 combinations.
10.
7C3 = 7*6*5/(3*2*1) = 35 combinations.7C3 = 7*6*5/(3*2*1) = 35 combinations.7C3 = 7*6*5/(3*2*1) = 35 combinations.7C3 = 7*6*5/(3*2*1) = 35 combinations.
You can make 5 combinations of 1 number, 10 combinations of 2 numbers, 10 combinations of 3 numbers, 5 combinations of 4 numbers, and 1 combinations of 5 number. 31 in all.
There are 120 permutations and 5 combinations.
5*4*3*2*1 = 120 combinations. * * * * * No. The previous answerer has confused permutations and combinations. There are only 25 = 32 combinations including the null combinations. There is 1 combination of all 5 numbers There are 5 combinations of 4 numbers out of 5 There are 10 combinations of 3 numbers out of 5 There are 10 combinations of 2 numbers out of 5 There are 5 combinations of 1 numbers out of 5 There is 1 combination of no 5 numbers 32 in all, or 31 if you want to disallow the null combination.
3 x 5 = 15
3*5*8 = 120
There are 1140 5 digit combinations from 1 to 20. 20 combination 3 computes that.
There are 21 ways to distribute the 7 books among the 3 individuals such that 2 books go to Robin and Lily, and 3 books go to Alexandria. This can be calculated using the formula for combinations: C(7, 2) * C(5, 3) = 21.
It can have 120 combinations . . .
90