It is 1*5C3*(4*3*2*1) = 240
120
240
There are 4 letters in IOWA, all non repeating. Arrangements are 4! or 24.
64 different arrangements are possible.
The number of arrangements of the letters PARTY, if the first letter must be an A is the same as the number of arrangements of the letters PRTY, and that is 4 factorial, or 24.
If you pick from each of the possible letters at each stage, then there are 5 possible options for the first letter. Then there are 4 possible options for the second. Then there are 3 possible options for the 3rd and so on. This leaves us with 5x4x3x2 = 120 different arrangements. However, each arrangement has been counted twice, as it doesn't matter which way around the Os go. So to get the true answer, we need to divide by 2. 120/2 = 60, and therefore the number of different arrangements of the letters in the word COLOR is 60.
There are 6!/(3!*2!) = 60 arrangements.
from itertools import permutationsfrom string import joinarrangements = [ ]for p in permutations ( 'ugccsir', 6 ) :arrangement = join ( p, '' )if 'ui' in arrangement :continueif not arrangement in arrangements :arrangements . append ( arrangement )print len ( arrangements )The above Python code gives a result of 2,220.
There are 5*4*3 = 60 arrangements.
There are (1*5*4)*(3*2*1) = 120 arrangements.
There are 5 letters: a c e f and h.If the letters can be repeated, then there are five possibilities for each space in the four-letter arrangement. The number of arrangements then is:5*5*5*5 = 54 = 625.
120
Answer: 7P4 = 840 arrangementsNumber of letters in the word ENGLISH : 7Number of letters to take: 4Number of arrangements:= 7P4= 7!/(7-4)!= 5040/6= 840
There are 12 two letter arrangements of the letters in PARK.
The correct arrangement is EQUAL.
There are 4 letters in IOWA, all non repeating. Arrangements are 4! or 24.
There are 7!/(2!*2!) = 1260 arrangements.
There are 172 different arrangements.
64 different arrangements are possible.