Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
xy - 4
0.5xy or xy/2
Suppose the numbers are x and y. The sum of their reciprocals = 1/x + 1/y = y/xy + x/xy = (y+x)/xy = (x+y)/xy = 10/30 = 1/3
xy-3 where x and y are the two numbers.
If the two numbers are x and y, thenthe square of the two numbers is one => (xy)^2 = 1 which implies that xy = +/-1.Then xy is a maximum => xy = 1.
The answer depends on whether xy are commutative numbers or operators in a permutation group.
Kyle XY was technically, a test tube baby. He didn't need an embylical chord, so he didn't have a belly button.
In the series kyle xy the part that is missing is his belly button
Suppose the two numbers are x and y. Then, the sum of THEIR reciprocals is 1/x + 1/y = y/xy + x/xy = (y + x)/xy = 7/25
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
3-xy ...i think * * * * * Good try, but actually, it is xy - 3
xy - 4
xy +7
0.5xy or xy/2
xy - 4
xy - 5