PQR P=2 Q=4 R=5 2 x 4 x 5 = 40
32
I
If P varies jointly as q, r and s - assume this is in direct proportion, then P ∝ qrs so P = kqrs where k is a constant.70 = k x 7 x 5 x 4 = 140k : k = 140/70 = 0.5When q = 2, r = 15 and s = 7 then,P = 0.5 x 2 x 15 x 7 = 105
S = 2 pi r h + 2 pi r2S - 2 pi r2 = 2 pi r hh = (S - 2 pi r2) / (2 pi r)
E = I R = (2) (6) = 12 volts
-11
Surface Area = pi*r*s + pi*r*r = 3.14*2*9 + 3.14*2*2
Probably not, though it is hard to work out the mapping "r equals 1 2"
C=2(pi)(r) therefore if r equals 3.20 then C=20.1061929
r=2
PQR P=2 Q=4 R=5 2 x 4 x 5 = 40
14v
r9 - 6 = 12 then r is 2
If: C = 2r Then: r = C/2
T = RV 4 = R8 4/8 = R R = 1/2
3r-2 for r=65