Q: What is 0 times 2x?

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4

2X-3Y=0

2x - 4x + 3 = 0 -2x + 3 = 0 2x = 3 x = 3/2 = 1.5

If -2x +14 = 0, -2x = -14, or x = 7.

f(x)= (x-7) /(-2x+7)(2x+5) set -2x+7=0 -2x=-7 x=7/2 set 2x+5=0 2x=-5 x=-5/2 x=7/2 and x=-5/2 are vertical asymptotes.

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4

x2+2x=0 4x=0 x=0 if you meant soemthing times 2 plus 2 times x =0 solve for x then y2+2x=0 y+x=0 x=-y so if x is 2 y is -2, if x is 100 y is -100

Assuming that 4x2+2x = 0: 2x (2x+1) = 0 2x = 0 or 2x+1 = 0 x = 0 or -1/2

2x + 3 = 3 Subtract '3' from both sides 2x = 0 x = 0 The answer!!!!!

4x2-2x = 0 2x(2x-1) = 0 x = 0 or x =1/2

It is 2x+(-2x) = 0

2X-3Y=0

0

Assume the number is x, then 2x + 3 = 3. This means 2x = 0. The result is x = 0

Let the required number be equal to x According to the given equation 2/3 of x= 8(-x) 2x/3= -8x 2x/3+(-8x)=0 2x/3-8x=0 2x/3-24x/3=0 -21x/3=0 -21x=0 x=0/-21 x=0 Hence the number would be 0.

y=2x y-2x=0 or 2x-y=0

2x = 2x + 0 Hence the constant term is 0 (zero)