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What is 1 2s of 10?

Updated: 4/28/2022
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if you mea 1/2 of 10 the answer is 5. if you mean what is 1 2/10 the answer is 2.

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Q: What is 1 2s of 10?
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How many hydrogen atoms are in 4.10 mol of ammonium sulfide?

(NH4)2S 4.10 moles (NH4)2S (8 moles H/1 mole (NH4)2S)(6.022 X 10^23/1 mole H) = 1.98 X 10^25 atoms of hydrogen


If 2 sandwiches and 1 drink is 10.00 1 sandwich and 2 drinks is 8.00 How much is each sandwich?

This is easy. Make two equations, and represent the sandwiches with s and the drink with d. you get: 2s+d=10 s+2d=8 After simplifying and taking away a variable, you figure out that each sandwich costs 4 dollars and each drink costs 2 dollars. (Heres the step by step algebra) 2s +dy = 10 s + 2d = 8 2s + d = 10 2s + 4d = 16 3d = 6 d = 2 2s + d = 10 2s + 2 = 10 2s = 8 s = 4 So, Sandwich = £4 Drink = £2


How do you determine the equation for the perpendicular bisector of the straight line joining the points s 2s and 3s 8s?

A = (s, 2s), B = (3s, 8s) The midpoint of AB is C = [(s + 3s)/2, (2s + 8s)/2] = [4s/2, 10s/2] = (2s, 5s) Gradient of AB = (8s - 2s)/(3s - s) = 6s/2s = 3 Gradient of perpendicular to AB = -1/(slope AB) = -1/3 Now, line through C = (2s, 5s) with gradient -1/3 is y - 5s = -1/3*(x - 2s) = 1/3*(2s - x) or 3y - 15s = 2s - x or x + 3y = 17s


Is it possible to get 10 using 3 2s?

no.


What is 4s plus 10 equals 2s plus 2?

It is a simple linear equation in 's'. Its solution is the number that 's' must bein order to make it a true statement. The solution may be found like this:4s + 10 = 2s + 2Subtract 10 from each side of the equation:4s = 2s - 8Subtract 2s from each side:2s = -8Divide each side by 2 :s = -4


What is the sum of one-half of s one-fifth of x and 7?

(1/2s)+(1/5x)+7 5s+2x+7 5s=2x+7 s=2/5x+7/5 (1/2(2/5x+7/5))+(1/5x)+7 1/5x+3.5/5+1/5x+7 2/5x+7 7/10 2/5x=-7 7/10 x=-19.25 (1/2s)+(1/5x)+7 1/2s-3.85+7 1/2s+3.15 1/2s=-3.15 s=-6.3 (1/2s)+(1/5x)+7 1/2(-6.3)+1/5(-19.25)+7 -3.15-3.85+7 0 In the end, it equals 0 because there were no values for x and s and since I started with just an equation with nothing on the other side, I used (by default) 0 on the other side.


What is the perpendicular bisector equation joining the points of s 2s and 3s 8s on the Cartesian plane showing work?

Points: (s, 2s) and (3s, 8s) Slope: (8s-2s)/(3s-s) = 6s/2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) => 3y-15s = -1(x-2s) => 3y = -x+17x Perpendicular bisector equation in its general form: x+3y-17s = 0


What is 2s plus 17 equals 2s plus 17?

2s + 17 = 2s + 17 1) First, you want to start on the left side of the equation and subtract 17 from both sides. 2s = 2s 2) Then, you take the 2 on the left side and divide it on both sides. s = s 3) You are left with s (Or 1s) on both sides, so s = 1.


What is the probability the number contains at least one digit 2?

The probability is 1. And the same is true for any other digit.This counter-intuitive result can be proved as follows:Ignore numbers with leading zeros.There are 9 1-digit numbers of which 8 do not contain any 2s;There are 90 2-digit numbers of which 8*9 do not contain any 2s;There are 900 3-digit numbers of which 8*9*9 do not contain any 2s;and so on.The total number of k digit numbers is 9 + 90 + 900 + ... + 9*10^(k-1)= 9*[10^k-1]/[10 - 1] = 10^k - 1Of these, the count of numbers which do not contain any 2s = 8 + 8*9 + 8*9^2 + ... + 8*9^(k-1)= 8*[9^k-1]/[9 - 1] = 9^k - 1So the probability that the numbers do not contain any 2s is [9^k - 1]/[10^k - 1] which, as k gets larger, approaches 9^k/10^k = (0.9)^k which tends to 0.So, the probability that the number DOES contain at least one 2 = 1 - Pr(It contains none) = 1 - 0 = 1.


What is the perpendicular bisector equation of a line joined by the points of s 2s and 3s 8s showing key stages of work?

It is found as follows:- Points: (s, 2s) and (3s, 8s) Slope: (2s-8s)/(s-3s) = -6s/-2s = 3 Perpendicular slope: -1/3 Midpoint: (s+3s)/2 and (2s+8s)/2 = (2s, 5s) Equation: y-5s = -1/3(x-2s) Multiply all terms by 3: 3y-15s = -1(x-2s) => 3y = -x+17s In its general form: x+3y-17s = 0


How many 2s can go into 102?

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How many 2s are there in 1-200?

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