It is a simple linear equation in 's'. Its solution is the number that 's' must bein order to make it a true statement. The solution may be found like this:4s + 10 = 2s + 2Subtract 10 from each side of the equation:4s = 2s - 8Subtract 2s from each side:2s = -8Divide each side by 2 :s = -4
If you mean: 4(2s-1) = 7s+12 then the value of s works out as 16
300 sir
3s + 4t + 2s + 5s + 6tGroup all of the like 's' terms & 't' terms together:(3s+2s+5s) + (4t + 6t)10s + 10t or 10(s+t)
Take $10 off the boots cost to get down to twice the cost of the shoes, and then halve that number to get the shoes cost: $76.50 - $10.00 = $66.50; half of that is $33.25. Algebraically, represent your knowns and relationships as equations and then solve them simultaeously for s: * b = 76.5; 2s + 10 = b * 2s + 10 = 76.5 * 2s = 66.5 * s = 66.5/2 * s = 33.25 dollars
It is a simple linear equation in 's'. Its solution is the number that 's' must bein order to make it a true statement. The solution may be found like this:4s + 10 = 2s + 2Subtract 10 from each side of the equation:4s = 2s - 8Subtract 2s from each side:2s = -8Divide each side by 2 :s = -4
(1/2s)+(1/5x)+7 5s+2x+7 5s=2x+7 s=2/5x+7/5 (1/2(2/5x+7/5))+(1/5x)+7 1/5x+3.5/5+1/5x+7 2/5x+7 7/10 2/5x=-7 7/10 x=-19.25 (1/2s)+(1/5x)+7 1/2s-3.85+7 1/2s+3.15 1/2s=-3.15 s=-6.3 (1/2s)+(1/5x)+7 1/2(-6.3)+1/5(-19.25)+7 -3.15-3.85+7 0 In the end, it equals 0 because there were no values for x and s and since I started with just an equation with nothing on the other side, I used (by default) 0 on the other side.
2s + 17 = 2s + 17 1) First, you want to start on the left side of the equation and subtract 17 from both sides. 2s = 2s 2) Then, you take the 2 on the left side and divide it on both sides. s = s 3) You are left with s (Or 1s) on both sides, so s = 1.
1
If you mean: 4(2s-1) = 7s+12 then the value of s works out as 16
It has 17 of them with a remainder of 1
Yes
If p = 2s + 5, then s = (p-5)/2 or 1/2 (p-5) --- p = 2s +5 p-5 = 2s (p-5)/2 = s
There are 202 2s from 1 to 512.
There are 3.99 x 10^24 hydrogen atoms in 8.30 moles of ammonium sulfide. This is calculated by multiplying Avogadro's number (6.022 x 10^23) by the number of hydrogen atoms in one molecule of ammonium sulfide (NH4)2S, which is 8.
300 sir
s=4