5a2 - 20ab - 25b2 = 5(a2 - 4ab - 5b2) = 5(a2 - 4ba - 5b2) since -5b*b = -5b2 and -5b + b = -4b, then = 5(a - 5b)(a + b)
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
24a2
5a times 3a minus 8a = (5*3)*a2 - 8a = 15a2 - 8a
8a+48b=
5a2 - 20ab - 25b2 = 5(a2 - 4ab - 5b2) = 5(a2 - 4ba - 5b2) since -5b*b = -5b2 and -5b + b = -4b, then = 5(a - 5b)(a + b)
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
24a2
15a + 20ab = zero5a(3 + 4b) = zerp5a=zero ............ a=zeroor3 + 4b = zero4b = -3 ............ b=-3/4
In its most simplified form: = 12abc + 8bc - 20ab = 4b(3ac + 2c - 5a) = 4b[(c + 5/3)(3a + 2) - 10/3]
5a times 3a minus 8a = (5*3)*a2 - 8a = 15a2 - 8a
8a+48b=
The GCF is 8a.
8a-3b = 5
8a-a-a = 6a
8a - 15 = -3 8a = 15 - 3 8a = 12 a = 12/8 = 6/4 = 3/2
8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.