20ab -8a squared = 12
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5a2 - 20ab - 25b2 = 5(a2 - 4ab - 5b2) = 5(a2 - 4ba - 5b2) since -5b*b = -5b2 and -5b + b = -4b, then = 5(a - 5b)(a + b)
This is not a difficult factorisation, as it is merely a normal factorisation with "a" stuck on the end of each number. 25a(2) - 20ab + 4b(2) (2b-5a)(2b-5a) This is: 2bx2b=4b(2) 2bx-5a=-10ab (twice) -5ax-5a=25a
24a2
8a+48b=
8A + (8A+8) + (8A+16) = 888 24A + 24 = 888 ===> 24A = 864 ===> A = 36 The multiples are 8A, 8A+8, 8A+16 = 288, 296, 304. Sum = 888.