within the equation 2x-3*4 you have 2x-12 but if you brake it down more you will have x= -6
Chat with our AI personalities
2x3 + 8x2 + 3x + 12 = (2x3 + 8x2) + (3x + 12) = 2x2(x + 4) + 3(x + 4) = (x + 4)(2x2 + 3) Since you have asked this question I am assuming that you are not yet at a level where you might want (2x2 + 3) factorised into its imaginary factors.
the answer is 6
(3x4 + 2x3 - x2 - x - 6)/(x2 + 1)= 3x2 + 2x - 4 + (-3x - 2)/(x2 + 1)= 3x2 + 2x - 4 - (3x + 2)/(x2 + 1)where the quotient is 3x2 + 2x - 4 and the remainder is -(3x + 2).
I'm going to assume the polynomial in question is 2x7+(3-2x3)+(5x8-4x) Expanding out the polynomial: 2x7+3-2x3+5x8-4x Order the terms by powers of x: 5x8+2x7-2x3-4x+3 Since 8 is the highest power of x, the degree of the polynomial is 8.
Factor out a 2. 2(x3 - 21x + 20) That factors to 2(x - 1)(x - 4)(x + 5) The roots are -5, 1 and 4