2y = -6x + 8 The y intercept occurs when x = 0 2y = 8 therefore y = 4
5y+8=7y 2y=8 y=4
4x+2y-8=0 2y=8-4x y=4-2x slope= -2
If: x -2y = 1 then x = 1+2y If: 3xy -y^2 = 8 then 3(1+2y)y -y^2 = 8 So: 3y+6y^2 -y^2 = 8 => 3y+5y^2 -8 = 0 Solving the above quadratic equation: y = 1 or y = -8/5 By substitution the points of intersection are at: (3, 1) and (-11/5, -8/5)
-4x=2y-16 +16 +16 (-4x+16)=(2y) /2 /2 y=-2x+8
If: 2y-10 = 8 Then: y = 9
2y=8..... y=4
2y = -6x + 8 The y intercept occurs when x = 0 2y = 8 therefore y = 4
y=4
Yes, 2y = 8 is a linear function. 2y = 8 is the same as y=8/2, or y=4, which is a vertical line.
x = 8 and y = 0
4x + 2y = -8 → 2y = -4x - 8 → y = -2x - 4
If you mean: 3x+2y = 16 then it is y = -1.5x+8
3y-8+5y = 2y-39 3y+5y-2y = -39+8 6y = -31 y = -31/6
y2 - 2y - 8 = (y - 4)(y + 2) = 0; whence, y = 4 or -2.
the answer is 42
x = 2y = 4