3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
Multiply first equation by 2: 4x - 2y = 20 Subtract second equation: x = 12, so y = 14.
If: x-2y = 1 then x = 2y+1 If: 3xy -y^2 = 8 then 3*(2y+1)*y -y^2 = 8 So: 6y^2 +3y -y^2 = 8 or 5y^2 +3y -8 = 0 Factorizing the above: (y-1)(5y+8) = 0 meaning y = 1 or y = -8/5 Solutions by substitution are: (3, 1) and (-11/5, -8/5)
4x-2y=16 has the solution points (0,-8) and (4, 0) at the coordinate axes, and wherever y= 4(x-4).
3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.
-2y=x+8 is the answer
Solve for y: 2x+2y=8 2y=-2x+8 y=-x+4 f(x)=-x+4 I think that's what you mean.
If 3y = 12, 2y = 8
-4x=2y-16 +16 +16 (-4x+16)=(2y) /2 /2 y=-2x+8
It's a simple linear equation in 'y'.To find the solution:7y - 8 = 2y + 37Subtract 2y from each side of the equation:5y - 8 = 37Add 8 to each side:5y = 45Divide each side by 5:y = 9
If: 2y-10 = 8 Then: y = 9
When graphed, or written in the form [ y = f(x) ], the slope is -3 .
since Y=8 and your equation is 2Y then it would be 2X8=16.
3x + 2y = 8 This is an equation. It could be the equation of a line.