3+w is the simplest expression of this problem.
3w
-3
w + 3
As a quadratic expression it is: w^2 +10w +21
(w² + 5w + 6) / (w² - w - 12)= [(w + 2)(w + 3)] / [(w - 4)(w + 3)]= (w + 2) / (w - 4)
11 + 5w
(t-7)/w = (-3-7)/-2 = -10/-2 = +5 ( minus over minus = plus)
36ong +36ong 612ght w=3 r=6 i=12
Three plus w.
6 plus w
whats w stand for? -7w + 3(w+2)= -14
As a quadratic expression it is: w^2 +10w +21
W/3 + 2W/3 is one possible answer.
(w² + 5w + 6) / (w² - w - 12)= [(w + 2)(w + 3)] / [(w - 4)(w + 3)]= (w + 2) / (w - 4)
w + 3 = 4w - 6 9 = 3w w = 3
-3
w+3=w+6 obviously doesn't equal itself... subtract w from both sides and you are left with 3=6 So the answer is NO SOLUTION, or as a set, it is the empty or null set.
-4
11 + 5w
6w