3+w is the simplest expression of this problem.
As a quadratic expression it is: w^2 +10w +21
11 + 5w
Ah, math time, my favorite! To reduce the fraction w^2 + 5w + 6 over w^2 - w - 12, first factor both the numerator and the denominator. The numerator factors into (w + 2)(w + 3), and the denominator factors into (w + 3)(w - 4). Cancel out the common factor of (w + 3) in both the numerator and the denominator, leaving you with (w + 2) over (w - 4). Voilà!
36ong +36ong 612ght w=3 r=6 i=12
5w+3 = 33 5w = 30 w = 6
Three plus w.
6 plus w
whats w stand for? -7w + 3(w+2)= -14
As a quadratic expression it is: w^2 +10w +21
W/3 + 2W/3 is one possible answer.
w + 3 = 4w - 6 9 = 3w w = 3
-3
-4
w+3=w+6 obviously doesn't equal itself... subtract w from both sides and you are left with 3=6 So the answer is NO SOLUTION, or as a set, it is the empty or null set.
11 + 5w
6w
(2w + 3)(w + 5)