Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals".
There are no operator symbols before 3a and 3b.
It is an expression that can be simplified to: 3a-2b+c
8a+2b
3a + 2b is an expression in algebra. If you make 3a + 2b equal to something then you can find the values of "a" and "b" Lets say you make 3a + 2b equal to 23 3a + 2b = 23 Now find "a" and "b" to make this equation true... 3(5) + 2(4) = 23 15 + 8 = 23 23 = 23 Correct So in this case a=5 and b=4
3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
3a + 2b = (3*6) + (2*5) = 18 + 10 = 283a+2b= (3x6)+(2x5)= 18+10=28
It is an expression that can be simplified to: 3a-2b+c
2a+2b+3a+3b+a+b= 6a+6b 2a+3a+a=6a 2b+3b+b=6b
3a + 2b = c (find a in terms of b and c)3a +2b -2b = c - 2b3a = c - 2b3a/3 = (c - 2b)/3a = (c - 2b)/3In order to find the value of a, you can give any values to b, and c (except a zero value).
8a+2b
It is an algabraic expession without knowing whether or not 2b and 3a are plus or minus
What is the answer of (3a+7b) (3a-7b)?
3a + 2b is an expression in algebra. If you make 3a + 2b equal to something then you can find the values of "a" and "b" Lets say you make 3a + 2b equal to 23 3a + 2b = 23 Now find "a" and "b" to make this equation true... 3(5) + 2(4) = 23 15 + 8 = 23 23 = 23 Correct So in this case a=5 and b=4
Well if you are adding you would have 8a+2b subtract you would have -2a+2b
3ab + 3ac + 2b2 + 2bc = 3a(b + c) + 2b(b + c) = (3a + 2b)(b + c)
Change the order to make it more obvious: 3a - a + 2b + 4b 2a + 6b or 2 (a + 3b).
(1) x/12=a+9, where a is an integer (2) x/18=b+9, where b is an integer 3x(1) + 2x(2) gives 3x/36 + 2x/36 = 5x/36 = 3a+27+2b+18 = 3a+2b+45 5x/36=3a+2b+45 x=36(3a+2b+45)/5 x=36(3a+2b)/5+9 as 36 is not divisible by 5 then 3a+2b should be divisible by 5 then the smallest solution is a=0 and b=0 and x=9
5ab(3a - 2b)