1.5
Chat with our AI personalities
If 3y = 12, 2y = 8
5x + (3y-x) + (10-2y) = 5x + 3y - x + 10 -2y = 5x - x + 3y - 2y + 10 = 4x + y +10
X + 3y - 2y + 3y = X + (3-2+3)y = X + 4y
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6
I don't know whether it's y^2-3y+2+3y-4y-5 or 2y-3y+2+3y-4y-5, so I'll do both.y^2-3y+2+3y-4y-5y^2+(-3y+3y-4y)+(2-5); group them togethery^2+(-4y)+(-3)y2-4y-3OR2y-3y+2+3y-4y-5(2y-3y+3y-4y)+(2-5); group them together(-2y)+(-3)-2y-3