If 3y = 12, 2y = 8
5x + (3y-x) + (10-2y) = 5x + 3y - x + 10 -2y = 5x - x + 3y - 2y + 10 = 4x + y +10
X + 3y - 2y + 3y = X + (3-2+3)y = X + 4y
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6
I don't know whether it's y^2-3y+2+3y-4y-5 or 2y-3y+2+3y-4y-5, so I'll do both.y^2-3y+2+3y-4y-5y^2+(-3y+3y-4y)+(2-5); group them togethery^2+(-4y)+(-3)y2-4y-3OR2y-3y+2+3y-4y-5(2y-3y+3y-4y)+(2-5); group them together(-2y)+(-3)-2y-3
if you wish to multiply 3y-2y by 3y-y the answer is 2y^2
2y - 3y = -1y
If 3y = 12, 2y = 8
3y squared - 2y = 1
It is y+3y-2y = 2y simplified
5 - 2y = -3y - 2Subtract 5 from each side:-2y = -3y - 7Add 3y to each side:y = -7
5y-2y= 3y+2 5y-2y-3y= 2 0y= 2
3y - 3 = 2y + 5 3y - 2y = 5 + 3 y = 8
5x + (3y-x) + (10-2y) = 5x + 3y - x + 10 -2y = 5x - x + 3y - 2y + 10 = 4x + y +10
Then 3y+1-2y can be simplified to y+1
X + 3y - 2y + 3y = X + (3-2+3)y = X + 4y
2y + 3 = 3y + 9 2y - 3y = 9 - 3 or -y = 6 so y = -6