The division of 402 by 67 results in a quotient of approximately 6 with a remainder of 0. To calculate this, you would perform long division, dividing 402 by 67. The quotient is the whole number result of the division, and the remainder is the amount left over after the division is complete.
201
402
2 x 3 x 67 = 402 2 x 201 = 402 3 x 134 = 402 6 x 67 = 402 To solve such a problem you use prime decomposition: This allows you to break any integer down into a multiple of prime numbers as in 2x3x67=402. Two, Three and 67 are all prime. From there to find all possible options, multiply the primes together: 2x3x67=402 --> 3x67=201 --> 2x201=402 2x3x67=402 --> 2x67=134 --> 3x134=402 2x3x67=402 --> 2x3=6 --> 6x67=402 This is under the assumption that this problem is restricted to integers. If real numbers are used, there are infinitely many solutions:
804 is divisible by: 1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402, 804.
67
67
402 = 2 * 3 * 67
The factors of 402 are: 1, 2, 3, 6, 67, 134, 201, and 402.The prime factors of 402 are: 2, 3, and 67.
1, 2, 3, 6, 67, 134, 201, 402 1, 2, 3, 6, 67, 134, 201, 402
134 over 402 = 67/201
6 x 67 = 402
201
402 = 2 x 3 x 67
Yes, 67 times 6 equals 402.
As a product of its prime factors: 2*3*67 = 402
2 x 3 x 67 = 402
402