201
402
2 x 3 x 67 = 402 2 x 201 = 402 3 x 134 = 402 6 x 67 = 402 To solve such a problem you use prime decomposition: This allows you to break any integer down into a multiple of prime numbers as in 2x3x67=402. Two, Three and 67 are all prime. From there to find all possible options, multiply the primes together: 2x3x67=402 --> 3x67=201 --> 2x201=402 2x3x67=402 --> 2x67=134 --> 3x134=402 2x3x67=402 --> 2x3=6 --> 6x67=402 This is under the assumption that this problem is restricted to integers. If real numbers are used, there are infinitely many solutions:
67 can be divided by 67 and 1.
804 is divisible by: 1, 2, 3, 4, 6, 12, 67, 134, 201, 268, 402, 804.
67
402 = 2 * 3 * 67
The factors of 402 are: 1, 2, 3, 6, 67, 134, 201, and 402.The prime factors of 402 are: 2, 3, and 67.
1, 2, 3, 6, 67, 134, 201, 402 1, 2, 3, 6, 67, 134, 201, 402
134 over 402 = 67/201
6 x 67 = 402
201
402 = 2 x 3 x 67
Yes, 67 times 6 equals 402.
As a product of its prime factors: 2*3*67 = 402
2 x 3 x 67 = 402
402