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9y+3 = 5y+13 9y-5y = 13-3 4y = 10 y =2.5
-3x = 3 + y 3 + y - 5y = -21 -4y = -24 y = 6 x = -3
5y3 - 125y = 5y(y2-25) = 5y (y+5)(y-5)
If the inequality is > (greater than) or >= (greater than or equal to), then there are an infinite number of solutions. So let the inequality be < (less than) or <= (less than or equal to) x = 1: 5y <= 16 so y = 1, 2 or 3 x = 2: 5y <= 12 so y = 1 or 2 x = 3: 5y <= 8 so y = 1 x >= 4: 5y <= 4 no solution. So whether the inequality is < or <= there are 6 ordered pairs.
2ay2 + 5ay - 3a = a(2y2 + 5y - 3) = a(2y - 1)(y + 3)