Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
(8+6i)-(2+3i)=6+3i 8+6i-2+3i=6+9i
60
6.3246 (rounded)
Square root of 25 = +or- 5 Square root of -36 = +or- 6i where i is the imaginary number such that i^2=-1 Square root of 121 = +or-11 So the 8 possible answers are: -16-6i, -16+6i, -6-6i, -6+6i, 6-6i, 6+6i, 16-6i and 16+6i
2+6i
564
A complex number is x+iy and -6i is 0-6i or 0-i6 I would then answer yes.
-6i-8
how can i unistall developer 6i from my winows7
The expression to simplify is 4+6i+7 Answer: 6i + 11
-5-7=-126i-8i=-2i-12-2i is your final answer
10 + 6i and 7 + 2i = 10 + 6i + 7 + 2i = 17 + 8i
(8+6i)-(2+3i)=6+3i 8+6i-2+3i=6+9i
6i*sqrt(5) is irreducable and is about 13.4164i
Oh, dude, the complex conjugate of 8 + 6i is just flipping the sign of the imaginary part, so it's 8 - 6i. It's like changing your mood from happy to grumpy, but in the world of math. So yeah, that's the deal with complex conjugates.