6 -- abc, acb, bac, bca, cab, cba
∠DAB + ∠EBA = 180� ⇒ 2∠CAB + 2∠CBA = 180� (Using (1) and (2)) ⇒ ∠CAB + ∠CBA = 90� In ∆ABC, ∠CAB + ∠CBA + ∠ABC = 180� (Angle sum property) ⇒ 90� + ∠ABC = 180� ⇒ ∠ABC = 180� - 90� = 90� Thus, the bisectors of two adjacent supplementary angles include a right angle.
Well in general, the pattern for all combinations of three digits A, B, C will be: AAA, AAB, AAC, ABA, ABB, ABC, ACA, ACB, ACC, BAA, BAB, BAC, BBA, BBB, BBC, BCA, BCB, BCC, CAA, CAB, CAC, CBA, CBB, CBC, CCA, CCB, CCC
Say you have the letters A,B, and C. Here are all the possible combinations. * ABC * ACB * BAC * BCA * CAB * CBA So, 6 if you don't repeat any of the letters. If you DO repeat letters, then simply take the number of letters you have, (3 for instance), and multiply it to the power of the number of letters you have. So, for 3 letters, the formula would be 33 . Or if you had 4 letters it would be 44 and so on.
Acute: 0 < X < 90; Right: = 90; Obtuse: 90 < X < 180; Straight: = 180; Reflex: 180 < X < 360. The Acut, Right, Straight and Reflex are actually classifications of an angle. Naming of an angle is done by identifying the vertex and a combination of the vertex and points on the two rays. For example an angle with points ABC where B is the vertex and A and C are points on the accompanying rays may be named as angle B, angle ABC or angle CBA. These can be written with the symbol for angle placed before the B the ABC and the CBA.
6 -- abc, acb, bac, bca, cab, cba
There would be 6 combinations. Let A, B and C represent the 3 names. You could have the following combinations: ABC, ACB, BAC, BCA, CAB, CBA
You could write them out. ABC, ACB, BCA, BAC, CBA, CAB The mathematical way to do it is 3 x 2 x 1 = 6
CBA
You have 3 letters to be put into 3 spaces. You have 3 ways of choosing the first letter followed by only 2 ways of choosing the second, leaving only 1 way to place the third. So the number of ways of arranging the 3 letters is 3 x 2 x 1 = 6
Abc-cba-caba
There are many different ways to print out a random sequence of letters on the screen. I believe that the shortest possible line of code that does this is: System.out.println("abcdcba abc cba"); For a program, here is the shortest program that runs on a Java 1.6 compiler: public class A{public static void main(String... a){System.out.println("abcdcba abc cba"
∠DAB + ∠EBA = 180� ⇒ 2∠CAB + 2∠CBA = 180� (Using (1) and (2)) ⇒ ∠CAB + ∠CBA = 90� In ∆ABC, ∠CAB + ∠CBA + ∠ABC = 180� (Angle sum property) ⇒ 90� + ∠ABC = 180� ⇒ ∠ABC = 180� - 90� = 90� Thus, the bisectors of two adjacent supplementary angles include a right angle.
Well in general, the pattern for all combinations of three digits A, B, C will be: AAA, AAB, AAC, ABA, ABB, ABC, ACA, ACB, ACC, BAA, BAB, BAC, BBA, BBB, BBC, BCA, BCB, BCC, CAA, CAB, CAC, CBA, CBB, CBC, CCA, CCB, CCC
The first letter can be any one of 22. For each of these ...The second letter can be any one of the remaining 21. For each of these ...The third letter can be any one of the remaining 20.So the number of different 3-letter line-ups is (22 x 21 x 20) = 9,240.That's the answer if you care about the sequence of the letters, i.e. if you call ABC and ACB different.If you don't care about the order of the 3 letters ... if ABC, ACB, BAC, BCA, CAB, and CBA are allthe same to you, then there are six ways to arrange each group of 3 different letters.Then the total number of different picks is (9,240/6) = 1,540.
Any 3 from 6 is 6!/(3! x 3!) ie 720/36 which is 20: ABC/ABD/ABE/ABF/ACD/ACE/ACF/ADE/ADF/AEF/ BCD/BCE/BCF/BDE/BDF/BEF/CDE/CDF/CEF/DEF. If the order in which they can run is taken into account then that 20 must be multiplied by 6 viz: ABC/ACB/BAC/BCA/CAB/CBA etc
The VERTEX of the angle is always in the middle... so if it is angle ABC, then you can also name it CBA as long as the vertex letter is in the middle, usually there are only 2 ways to name an angle.Also, if there aren't any other angles with the same vertex, you can just call angle ABC, angle B.Summary: If you have an angle:the vertex is labeled B, the others are A and C. what can you call the angle?Answer: ABC,CBA or B