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'abc', 'acb', and 'cba' are all the same number.
459+495=954 so A is 4 B is 5 and C is 9
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How many ways can you arrange 3 things?
6 -- abc, acb, bac, bca, cab, cba
Prove that the bisectors of 2 adjacent supplementary angles include a right angle?
∠DAB + ∠EBA = 180� ⇒ 2∠CAB + 2∠CBA = 180� (Using (1) and (2)) ⇒ ∠CAB + ∠CBA = 90� In ∆ABC, ∠CAB + ∠CBA + ∠ABC = 180� (Angle sum property) ⇒ 90� + ∠ABC = 180� ⇒ ∠ABC = 180� - 90� = 90� Thus, the bisectors of two adjacent supplementary angles include a right angle.
How you can make All possible combinations of any three digits?
Well in general, the pattern for all combinations of three digits A, B, C will be: AAA, AAB, AAC, ABA, ABB, ABC, ACA, ACB, ACC, BAA, BAB, BAC, BBA, BBB, BBC, BCA, BCB, BCC, CAA, CAB, CAC, CBA, CBB, CBC, CCA, CCB, CCC
How many possible combinations of three letters are there?
Say you have the letters A,B, and C. Here are all the possible combinations. * ABC * ACB * BAC * BCA * CAB * CBA So, 6 if you don't repeat any of the letters. If you DO repeat letters, then simply take the number of letters you have, (3 for instance), and multiply it to the power of the number of letters you have. So, for 3 letters, the formula would be 33 . Or if you had 4 letters it would be 44 and so on.
What are three ways to name an angle?
Acute: 0 < X < 90; Right: = 90; Obtuse: 90 < X < 180; Straight: = 180; Reflex: 180 < X < 360. The Acut, Right, Straight and Reflex are actually classifications of an angle. Naming of an angle is done by identifying the vertex and a combination of the vertex and points on the two rays. For example an angle with points ABC where B is the vertex and A and C are points on the accompanying rays may be named as angle B, angle ABC or angle CBA. These can be written with the symbol for angle placed before the B the ABC and the CBA.
How many ways can you arrange 3 things?
6 -- abc, acb, bac, bca, cab, cba
If there are three names how many ways could you put them?
There would be 6 combinations. Let A, B and C represent the 3 names. You could have the following combinations: ABC, ACB, BAC, BCA, CAB, CBA
How do you figure out how many 3 letter combinations you can make out of 3 letters?
You could write them out. ABC, ACB, BCA, BAC, CBA, CAB The mathematical way to do it is 3 x 2 x 1 = 6
What is abc spelled bakwards?
CBA
How many ways can the letters ABC be arranged?
You have 3 letters to be put into 3 spaces. You have 3 ways of choosing the first letter followed by only 2 ways of choosing the second, leaving only 1 way to place the third. So the number of ways of arranging the 3 letters is 3 x 2 x 1 = 6
What is the Black Butler Item Code?
Abc-cba-caba
How do you print the pattern ABCdcba ABC cba?
There are many different ways to print out a random sequence of letters on the screen. I believe that the shortest possible line of code that does this is: System.out.println("abcdcba abc cba"); For a program, here is the shortest program that runs on a Java 1.6 compiler: public class A{public static void main(String... a){System.out.println("abcdcba abc cba"
Prove that the bisectors of 2 adjacent supplementary angles include a right angle?
∠DAB + ∠EBA = 180� ⇒ 2∠CAB + 2∠CBA = 180� (Using (1) and (2)) ⇒ ∠CAB + ∠CBA = 90� In ∆ABC, ∠CAB + ∠CBA + ∠ABC = 180� (Angle sum property) ⇒ 90� + ∠ABC = 180� ⇒ ∠ABC = 180� - 90� = 90� Thus, the bisectors of two adjacent supplementary angles include a right angle.
How you can make All possible combinations of any three digits?
Well in general, the pattern for all combinations of three digits A, B, C will be: AAA, AAB, AAC, ABA, ABB, ABC, ACA, ACB, ACC, BAA, BAB, BAC, BBA, BBB, BBC, BCA, BCB, BCC, CAA, CAB, CAC, CBA, CBB, CBC, CCA, CCB, CCC
Can angle ABC can be called angle cba?
Yes, so as long as the angle being identified (in this case, angle b) is in the center.
How many 3 letter combinations from 22 letters?
The first letter can be any one of 22. For each of these ...The second letter can be any one of the remaining 21. For each of these ...The third letter can be any one of the remaining 20.So the number of different 3-letter line-ups is (22 x 21 x 20) = 9,240.That's the answer if you care about the sequence of the letters, i.e. if you call ABC and ACB different.If you don't care about the order of the 3 letters ... if ABC, ACB, BAC, BCA, CAB, and CBA are allthe same to you, then there are six ways to arrange each group of 3 different letters.Then the total number of different picks is (9,240/6) = 1,540.
How many three-person relay teams can be chosen from six students?
Any 3 from 6 is 6!/(3! x 3!) ie 720/36 which is 20: ABC/ABD/ABE/ABF/ACD/ACE/ACF/ADE/ADF/AEF/ BCD/BCE/BCF/BDE/BDF/BEF/CDE/CDF/CEF/DEF. If the order in which they can run is taken into account then that 20 must be multiplied by 6 viz: ABC/ACB/BAC/BCA/CAB/CBA etc
