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Well in general, the pattern for all combinations of three digits A, B, C will be:

AAA, AAB, AAC, ABA, ABB, ABC, ACA, ACB, ACC, BAA, BAB, BAC, BBA, BBB, BBC, BCA, BCB, BCC, CAA, CAB, CAC, CBA, CBB, CBC, CCA, CCB, CCC

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Q: How you can make All possible combinations of any three digits?
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What combinations can you make with numbers 1472580?

You can make: 1 combination containing 0 digits, 7 combinations containing 1 digits, 21 combinations containing 2 digits, 35 combinations containing 3 digits, 35 combinations containing 4 digits, 21 combinations containing 5 digits, 7 combinations containing 6 digits, and 1 combinations containing 7 digits. That makes 2^7 = 128 in all.


What combinations can you make with numbers 1 4 7 2 5 8 0?

Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.


How many combinations can you make only using 4 7 8?

6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations


How many combinations can you make using 30 digits and what are they?

Yuo can make only one combination of 30 digits using 30 digits.


How many different combinations can you make using 2 3 6 and 9?

If you use them only once each, you can make 15 combinations. 1 with all four digits, 4 with 3 digits, 6 with 2 digits, and 4 with 1 digit. There is also a combination containing no digits making 16 = 24 combinations from 4 elements.


How many combinations can the digits 1 0 3 make?

9.


How do you make 3 even numbers out of 456?

456, 546 and 564 are three of the four possible even numbers.


If you wanted to know how many 5 digit combinations you could make using only 2 digits how would you solve this?

Simple enough to solve. The answer is a power of two. Assuming you have two possible digits, say for example, 3 and 4, then you simply have to multiply it by how many numbers you want to get the total number of combinations. Each number can be 3 or 4 in this case, and you have 5 numbers. That's two to the fifth. Five combinations of any two numbers. 2x2x2x2x2. The answer is 32 combinations.


If you have twenty four digits how many combinations of twelve can you make?

If you have 24 distinct characters, then there are 2,704,156 combinations of 12 characters. Normally there are only ten digits and so 24 of them would contain duplicates. In that case the answer will depend on the duplication.


How many three digit numbers can be made with 1 2 and 0 used repeatedly?

You can make 27 unique three-digit numbers using the three digits 0, 1, and 2.i.e. for each of the three digits abc, there are 9 possible orders of those, from aaa to ccc.The 9 starting with 0:000001002010011012020021022* the combinations are the same as the numbers 0 to 26 expressed in base 3 (000 to 222)26 base 3 = 222 = 18 + 6 + 2 = 26


How many one two or three digit combinations can you get using 1 2 and 3 in any one two or three configuration?

This question could would be best answered if you have a basic understanding of combinatorics (the study of combinations and permutations and probability) however, for something with as few possibilities as this, it is often easier to just make a list. Start with three digit combinations, then two digit combos, then one digit. Remember also that combinations are order independent ( ABC is the same thing as CBA) 3 digits 3 2 1 2 digits 3 2 3 1 2 1 1 digits 1 2 3 count those up and voila.


How many 5 numbers combinations can you make from 1 2 3 4 5?

If digits can be reused, then 5x5x5x5x5 = 3125. If digits cannot be reused, then 5x4x3x2x1 = 120.