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Well in general, the pattern for all combinations of three digits A, B, C will be:

AAA, AAB, AAC, ABA, ABB, ABC, ACA, ACB, ACC, BAA, BAB, BAC, BBA, BBB, BBC, BCA, BCB, BCC, CAA, CAB, CAC, CBA, CBB, CBC, CCA, CCB, CCC

Q: How you can make All possible combinations of any three digits?

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Yuo can make only one combination of 30 digits using 30 digits.

9,000 - all the numbers between 1,000 and 9,999 inclusive. * * * * * NO. Those are PERMUTATIONS, not COMBINATIONS. Also, the question specified 4 digit combinations using 4 digits. The above answer uses 10 digits. If you start with 4 digits, you can make only 1 combination.

If you have 24 distinct characters, then there are 2,704,156 combinations of 12 characters. Normally there are only ten digits and so 24 of them would contain duplicates. In that case the answer will depend on the duplication.

Only one: 2468. The order of the digits in a combination does not make a difference.

That depends on . . . -- how many digits you want in each combination -- whether it's allowed to repeat the same digit -- whether the order of the digits in the combination matters, i.e. whether you actually want combinations or permutations. Each choice has a different answer.

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You can make: 1 combination containing 0 digits, 7 combinations containing 1 digits, 21 combinations containing 2 digits, 35 combinations containing 3 digits, 35 combinations containing 4 digits, 21 combinations containing 5 digits, 7 combinations containing 6 digits, and 1 combinations containing 7 digits. That makes 2^7 = 128 in all.

Assuming the digits cannot be repeated, there are 7 combinations with 1 digit, 21 combinations with 2 digits, 35 combinations with 3 digits, 35 combinations with 4 digits, 21 combinations with 5 digits, 7 combinations with 6 digits and 1 combinations with 7 digits. That makes a total of 2^7 - 1 = 127: too many for me to list. If digits can be repeated, there are infinitely many combinations.

If the 6 digits can be repeated, there are 1296 different combinations. If you cannot repeat digits in the combination there are 360 different combinations. * * * * * No. That is the number of PERMUTATIONS, not COMBINATIONS. If you have 6 different digits, you can make only 15 4-digit combinations from them.

The number of possible 3 digit combinations you can make out of 1-9 with outrepeated digits is:9C3 = 9!/(3!(9-3)!) = 84

5040, assuming none of the digits are the same. (Assuming they're not, there's 5040 unique combinations you can make out of 7 digits).

6 for 3-digits, 6 for 2-digits, 3 for 1-digits, and 15 for all of the combinations

Assuming you are treating each number as a number and not as an individual unit, the numbers you can make from these digits are 899, 989 and 998.

Yuo can make only one combination of 30 digits using 30 digits.

There are infinite combinations that can make 3879

9.

If you use them only once each, you can make 15 combinations. 1 with all four digits, 4 with 3 digits, 6 with 2 digits, and 4 with 1 digit. There is also a combination containing no digits making 16 = 24 combinations from 4 elements.

The sum is 22 times the sum of the three digits.