729
729, cube of 9 and square of 27
121 is perfect three digit square palindrome. (11 x 11) So is 484 (22 x 22) and 676 (26 x 26)
Well, let's see. Perfect cubes that are two digits: 27 64 Could it be 27? Well, 2+7 is 9, and that's a perfect square with a square root of 3, and the cube root of 27 is three. Looks like we've found our answer, especially since 6+4 = 10, which is NOT a perfect square.
There are a total of 5 positive three-digit perfect cubes that are even. To find this, we first determine the range of three-digit perfect cubes, which is from 46 to 96. Then, we identify the even perfect cubes within this range, which are 64, 216, 512, 729, and 1000.
1
102 = 100 which is the first possible three digit number that is a perfect square. 312 = 961 which is the last possible three digit number that is a perfect square. So there are 22 three digit positive numbers that are perfect squares.
x64 is not a perfect square any number if it is a 3-digit perfect square and ending with 4 it can be 144,324 ,484 and 784 because the number is ending with 4 but the tens digit is not matching to any of the option so it is not a perfect square
729, cube of 9 and square of 27
No. The smallest 2 digit number is 10 the smallest 3 digit number is 100 - so the question is whether (100-10) is a perfect square? No - 90 is not a perfect square. 8x8 is 64 and 9x9 is 91, not 90.
It is 10.
961 961
One hundred is the least three-digit square number. It is formed by 102.
It is: 31*31 = 961
121 is perfect three digit square palindrome. (11 x 11) So is 484 (22 x 22) and 676 (26 x 26)
100
999
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