0.0409
41 OR 82
Let x represent the two digit number we seek.
Let y represent the whole integer of 171/x.
So 171/x=y+7/x
We can multiply x to both sides, making the equation this: 171=xy+7
Subtract 7 from both sides, we get 164=xy.
Now knowing that x is a two digit number and y has to be a whole integer, we use logic to arrive at the conclusion that x=41 and y=4 OR x=82 and y=2.
We can plug our solutions into the equation 171/x=y+7/x. Let's start with x=41 and y=4. 171/(41)=(4)+7/(41) = 4.17073=4.17073 ✔. We can also check x=82 and y=2. 171/(82)=(2)+7/(82) = 2.085365=2.085365 ✔. So in this case, we have more than one possible solution.
15
19
171 ÷ 2 = 85.5 or 85 times with a remainder of 1.
The largest 3 digit number which when divided by 69 and 12 to give a remainder of 1 is 829. What we want is one more than a common multiple of 69 and 12. The common multiples of 69 and 12 are the multiples of their least common multiple: 69 = 3 x 23 12 = 2^2 x 3 → lcm = 2^2 x 3 x 23 = 276 The largest multiple of 276 which is a 3 digit number: 999 ÷ 276 = 3 r 171 → largest 3 digit multiple of 276 is 3 × 276 = 828 → the required number is 828 + 1 = 829.
171 with remainder 3.
171 cannot go into ANY two digit number - its smallest positive multiple is 171. Therefore the remainder must be the original 2 digit number. However, the question states that the remainder is 6. That is a contradiction. Consequently, there cannot be any solution to the question as stated.
15
If the result has a remainder of 6, then the number must be 165 + 6. So you need to find all the 2-digit factors of 165. The easiest way is to just start listing them and see what you get. Start with 10, then go to 11, etc and write the factor pairs. If some number is not a factor of 165, just skip it and go to the next number. When the factors start to repeat, you are done. The two-digit factors of 165 10 × ___ <-- 10 is not a factor, so skip it and go to the next number 11 × 15 12 × ___ <-- Not a factor. Skip to the next number 13 × ___ <-- Not a factor 14 × ___ <-- Skip this one 15 × 11 <-- The factors are repeating, so you are done. Answer: The only two-digit numbers that divide 171 with a remainder of 6 are 11 and 15 Check 171 ÷ 11 = 15 R6 171 ÷ 15 = 11 R6 Check!
171 / <unknown> = <some number> remainder 7 First, 171-7=164 Purpose: all factors of 164 would be either <unknown> or <some number> 164= 1 x 164 2 x 83 Factors of 164: 1, 2, 83, 164 Since you wanted two digit numbers, the only answer is 83. Proof: 171 / 83 = 2 R 7 * * * * * The last time I checked, 2*83 was not 164, but 2 times 82 was. So, the correct answers are 82 and 41.
1.7812
171, remainder 4
The sum of the digits of 171 is 9.
19
A decimal number is simply a way of representing a number in such a way that the place value of each digit is ten times that of the digit to its right. A decimal representation does not require a decimal point. So the required decimal representation is 171, exactly as in the question.
I believe you would basically have to try out the divisions one by one - I am not aware of any great shortcut. You can do the divisions in Excel, using the mod() function. Another option is to write a short computer program that tests each of the divisions. (171 % 1, 171 % 2, 171 % 3... up to 171 % 171 - many programming language use the "%" sign for the remainder of a division). If you do the divisions by hand, you may notice certain patterns, and skip a few numbers in the divisions.
3.42
171 ÷ 2 = 85.5 or 85 times with a remainder of 1.