If the result has a remainder of 6, then the number must be 165 + 6.
So you need to find all the 2-digit factors of 165.
The easiest way is to just start listing them and see what you get.
Start with 10, then go to 11, etc and write the factor pairs.
If some number is not a factor of 165, just skip it and go to the next number.
When the factors start to repeat, you are done.
The two-digit factors of 165
10 × ___ <-- 10 is not a factor, so skip it and go to the next number
11 × 15
12 × ___ <-- Not a factor. Skip to the next number
13 × ___ <-- Not a factor
14 × ___ <-- Skip this one
15 × 11 <-- The factors are repeating, so you are done.
Answer:
The only two-digit numbers that divide 171 with a remainder of 6 are
11 and 15
Check
171 ÷ 11 = 15 R6
171 ÷ 15 = 11 R6
Check!
The ratio of the number of one-digit prime numbers to the number of one-digit composite numbers is one to one. The one-digit prime numbers are 2, 3, 5, and 7. The one-digit composite numbers are 4, 6, 8, and 9. Therefor, the ratio is 4:4, which simplifies to 1:1.
There are four of each.
The nth triangular number is given by ½ × n × (n+1)→ the 5857th triangular number is ½ × 5857 × 5858 = 17,155,153, so its units digit is a 3.------------------------------------------------------------Alternatively,If you look at the units digits of the first 20 triangular numbers they are {1, 3, 6, 0, 5, 1, 8, 6, 5, 5, 6, 8, 1, 5, 0, 6, 3, 1, 0, 0}At this stage, as we are only concerned with the units digit, as we now have a 0 for the units digit, when 21 is added it is the same as adding 1 to 0 to give a 1, for the 22nd triangular number, we are adding 2 to the 1 to give 3, and so on - the sequence of 20 digits is repeating.To find the units digit of the nth triangular number, find the remainder of n divided by 20 and its units digit will be that digit in the sequence (if the remainder is 0, use the 20th number). To find the remainder when divided by 20 is very simple by looking at only the tens digit and the units digit:If the tens digit is even (ie one of {0, 2, 4, 6, 8}), the remainder is the units digitIf the tens digit is odd (ie one of {1, 3, 5, 7, 9}), the remainder is the units digit + 10.5857 ÷ 20 = ... remainder 17; the 17th digit of the above sequence is a 3, so the units digit of the 5857th triangular number is a 3.This trick can be used for much larger triangular numbers which calculators cannot calculate exactly using the above formula. eg the units digit of the 1234567890123456789th triangular number is... 1234567890123456789 ÷ 20 = .... remainder 9, so this triangular number's units digit is the 9th digit of the above sequence which is a 5.
68686868
Routing number is 9 digit number.
A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.
84
The common factors of 609 and 957 are 1, 3, 29 and 87. No 3-digit numbers.
-3
Divide the two-digit number by the one-digit number. If the remainder is zero then the 2-digit number is a multiple and if not, it is not.
81 is.
Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.
2
I think you are talking about three numbers 743, 142, and 986425. If the least significant digit in a number is odd, the number is odd. If the least significant digit in a number is even, the number is even. You can also divide the number by 2 and if two goes into the number evenly without a remainder then the number is even. If there is a remainder, the number is odd.
mathematics
Regardless of the dividend (the number being divided), no divisor can produce a remainder equal to, or greater than, itself..... dividing by 4 cannot result in a remainder of 5, for example, Therefore the only single-digit number which can return a remainder of 8 is 9. 35 ÷ 9 = 3 and remainder 8
That's not possible. The largest single-digit number by which you might divide is 9. And, by definition, the remainder is always LESS than the number by which you divide. Thus, the largest remainder you can get, when you divide by 9, is 8.