arcus cosinus
http://en.wikipedia.org/wiki/Inverse_trigonometric_functions
arc cos -0.32 is approx: --------------- | 108.66° | ---------------
Oh, what a happy little question! To put arcsec in a calculator, you simply press the "2nd" or "Shift" key on your calculator, then find the "sec" button. This will allow you to calculate the arcsec of an angle and create beautiful mathematical landscapes. Just remember, there are no mistakes, only happy little calculations!
To find the angle between two vectors, you need to use this form: a ∙ b / (|ab|) = cos(θ) θ = arccos(a ∙ b / (|ab|)) where a and b are vectors. Compute the dot product and the norm of |a| and |b|. Then, compute the angle between the vectors.
If you have vectors U = (ai + bj + ck) and V = (di + ej + fk) and x is the angle between them, thencos(x) = U.V/(|U|*|V|)= (ad + be + cf)/[sqrt(a2+b2+c2)*sqrt(d2+e2+f2)]The angle x can be determined by calculating arccos of the above value.
Perhaps, related to "What is arccos(sqrt(Pi)/2)?" ... which is the trigonometric function that defines the vertex angle of a Pythagorean triangle that squares the circle: arccos(.88622692545275801364908374167057..) = 27.597112635690604451732204752339.. degrees. For a circle having a diameter equal to 2, the triangle's long side (circle's chord; side of its square) = sqrt(Pi) and its hypotenuse = 2 (circle's diameter), with the vertex point on the circumference.
arcsin(1) arccos(0)
0 is your answer tan(45)=1 and arccos(1)=0
f(x) = arccos(x) / 2 f'(x) = -1/(2√(1 - x2))
8
arc cos -0.32 is approx: --------------- | 108.66° | ---------------
Inverse of Cosine is 'ArcCos' or Cos^(-1) The reciprocal of Cosine is !/ Cosine = Secant.
I assume that you want to solve cos(x) = 2*pi, not pie! arccos(0.4) = 1.1593 radians. This is the solution in the range 0 to pi. There is another solution which is at 2*pi - 1.1593 = 5.1239 radians. Note that arccos appears on most calculators as "cos to the power -1".
Perhaps, related to "What is arccos(sqrt(Pi)/2)?" ... which is the trigonometric function that defines the vertex angle of a Pythagorean triangle that squares the circle: arccos(.88622692545275801364908374167057..) = 27.597112635690604451732204752339.. degrees. For a circle having a diameter equal to 2, the triangle's long side (circle's chord; side of its square) = sqrt(Pi) and its hypotenuse = 2 (circle's diameter), with the vertex point on the circumference.
This would be the arccos(21/25), which is 32.859880378889108736588042568 degrees! lol
arccos(0) = 90 + 360.n (n is an element of the integers) and 90 and 360 are in degrees. Therefore if the answer is in the subset 0<x<360 or something similar, Then the answer is 90.
Oh, what a happy little question! To put arcsec in a calculator, you simply press the "2nd" or "Shift" key on your calculator, then find the "sec" button. This will allow you to calculate the arcsec of an angle and create beautiful mathematical landscapes. Just remember, there are no mistakes, only happy little calculations!