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What is The value of arccos (-0.32) as a decimal to the nearest hundredth of a degree in the box.?
arc cos -0.32 is approx: --------------- | 108.66° | ---------------
How do I put arcsec in calculator?
Oh, what a happy little question! To put arcsec in a calculator, you simply press the "2nd" or "Shift" key on your calculator, then find the "sec" button. This will allow you to calculate the arcsec of an angle and create beautiful mathematical landscapes. Just remember, there are no mistakes, only happy little calculations!
How do you find angle between vectors?
To find the angle between two vectors, you need to use this form: a ∙ b / (|ab|) = cos(θ) θ = arccos(a ∙ b / (|ab|)) where a and b are vectors. Compute the dot product and the norm of |a| and |b|. Then, compute the angle between the vectors.
What is the angle in radians between the vectors?
If you have vectors U = (ai + bj + ck) and V = (di + ej + fk) and x is the angle between them, thencos(x) = U.V/(|U|*|V|)= (ad + be + cf)/[sqrt(a2+b2+c2)*sqrt(d2+e2+f2)]The angle x can be determined by calculating arccos of the above value.
What is arccos(sqrt(Pi))?
Perhaps, related to "What is arccos(sqrt(Pi)/2)?" ... which is the trigonometric function that defines the vertex angle of a Pythagorean triangle that squares the circle: arccos(.88622692545275801364908374167057..) = 27.597112635690604451732204752339.. degrees. For a circle having a diameter equal to 2, the triangle's long side (circle's chord; side of its square) = sqrt(Pi) and its hypotenuse = 2 (circle's diameter), with the vertex point on the circumference.
What is the tangent of 45º?
0 is your answer tan(45)=1 and arccos(1)=0
What trigonometric function gives the value of pi?
arcsin(1) arccos(0)
What is the derivative of arccosxdividedby2?
f(x) = arccos(x) / 2 f'(x) = -1/(2√(1 - x2))
Lesson 5-3 The inverse cosin function?
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What is The value of arccos (-0.32) as a decimal to the nearest hundredth of a degree in the box.?
arc cos -0.32 is approx: --------------- | 108.66° | ---------------
How do you solve cos x 0.4 for 0 to two pie?
I assume that you want to solve cos(x) = 2*pi, not pie! arccos(0.4) = 1.1593 radians. This is the solution in the range 0 to pi. There is another solution which is at 2*pi - 1.1593 = 5.1239 radians. Note that arccos appears on most calculators as "cos to the power -1".
what is sqrt(2)?
Perhaps, related to "What is arccos(sqrt(Pi)/2)?" ... which is the trigonometric function that defines the vertex angle of a Pythagorean triangle that squares the circle: arccos(.88622692545275801364908374167057..) = 27.597112635690604451732204752339.. degrees. For a circle having a diameter equal to 2, the triangle's long side (circle's chord; side of its square) = sqrt(Pi) and its hypotenuse = 2 (circle's diameter), with the vertex point on the circumference.
How do I put arcsec in calculator?
Oh, what a happy little question! To put arcsec in a calculator, you simply press the "2nd" or "Shift" key on your calculator, then find the "sec" button. This will allow you to calculate the arcsec of an angle and create beautiful mathematical landscapes. Just remember, there are no mistakes, only happy little calculations!
A water slide is a straight ramp 25 m longthat starts from the top of a tower 21 m high what is the angle the slide forms with the tower?
This would be the arccos(21/25), which is 32.859880378889108736588042568 degrees! lol
If y equals arc cos 0 then y is equal to 0 1 90 or 180?
arccos(0) = 90 + 360.n (n is an element of the integers) and 90 and 360 are in degrees. Therefore if the answer is in the subset 0<x<360 or something similar, Then the answer is 90.
How do you find the area of an isosceles triangle with 2 equal sides and 1 angle?
It really depends on the angle. If the angle is at the point where the two equal sides intersect then you can divide the triangle into two equal parts (forming a right angle with the base), divide the angle by two, then use the following equation(side*arccos(your angle/2))*((side*arcsin(your angle/2)))if the angle is not where the two equal sides intersect then you can divide the triangle into two equal parts (from the point where the two equal sides intersect down to a right angle with the base) then use the following equation.(side*arcsin(your angle)*(side*arccos(your angle))
