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x + 3y = 6

2x + y = -8

Solve by substitution:

x + 3y = 6 subtract 3y to both sides

x = 6 - 3y

2x + y = -8 substitute 6 - 3y for x

2(6 - 3y) + y = -8

12 - 6y + y = -8

12 - 5y = -8 subtract 12 to both sides

-5y = -20 divide by -5 to both sides

y = 4

x = 6 - 3y

x = 6 - 3(4) = 6 - 12

x = -6

Thus, the solution of the system is (-6, 4).

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16y ago

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