x + 3y = 6
2x + y = -8
Solve by substitution:
x + 3y = 6 subtract 3y to both sides
x = 6 - 3y
2x + y = -8 substitute 6 - 3y for x
2(6 - 3y) + y = -8
12 - 6y + y = -8
12 - 5y = -8 subtract 12 to both sides
-5y = -20 divide by -5 to both sides
y = 4
x = 6 - 3y
x = 6 - 3(4) = 6 - 12
x = -6
Thus, the solution of the system is (-6, 4).
Collect like terms: 2x + 3y + 3y - 5 - 6 2x + 6y - 11
2x + 3y = 6 can be written in the standard slope-intercept form of y= mx + c, where 'm' is the slope. 3y = -2x + 6 y = -⅔x + 2 The slope of this linear graph is -⅔.
Yes.
2. If x=5 & y =3 then: 3x + 2y = 3 x 5 + 2 x 3 = 15 + 6 = 21 2x + 3y = 2 x 5 + 3 x 3 = 10 + 9 = 19 ⇒ 3x+2y exceeds 2x+3y by 21 - 19 = 2. Alternatively: 3x+2y exceeds 2x+3y by: (3x+2y) - (2x + 3y) = 3x + 2y - 2x - 3y = x - y If x=5 & y=3 then this becomes: x - y = 5 - 3 = 2
8x-7 plus 2x equals 6 plus 5x plus 2?
2x-11
Collect like terms: 2x + 3y + 3y - 5 - 6 2x + 6y - 11
2x + 3y = 9x = 3, y = 1 therefore 6 + 3 = 9
2x+3y = 6 2x+3(0) = 6 2x = 6 x = 6/2 x = 3
2x - 3y = 6 2x = 6 + 3y 2x - 6 = 3y : 3y = 2x - 6 y = 2/3x - 2
Yes and it works out that x = 3 and y = 4
2x + 3y + 6 = 0Subtract (2x + 6) from each side:3y = -2x - 6Divide each side by 3:y = -(2/3)x - 2Slope = -(2/3)Y-intercept = -2
6x-y=-14 2x-3y=6
They are parallel lines.
y=x+5
2x + 3y = 6 can be written in the standard slope-intercept form of y= mx + c, where 'm' is the slope. 3y = -2x + 6 y = -⅔x + 2 The slope of this linear graph is -⅔.
Answer = -2x + 3y - 6 Are you sure you asked the question correctly?