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What is the exponential form of 2187?
The exponential form of 2187 is 3^7. This is because 3 raised to the power of 7 equals 2187. In exponential form, the base (3) is raised to the power of the exponent (7) to give the result (2187).
Given that p equals log2q find an expression in terms of p for log2 routeq and log2 8q?
log2 sqrt(q) = p/2 log2 8q = 3 + p And it is root, not route.
How do we change from logarithmic form to exponential form?
Logb (x)=y is called the logarithmic form where logb means log with base b So to put this in exponential form we let b be the base and y the exponent by=x Here is an example log2 8=3 since 23 =8. In this case the term on the left is the logarithmic form while the one of the right is the exponential form.
What is the exponential form of 53?
The exponential form of 53 is 5^3. In exponential form, the base (5) is raised to the power of the exponent (3), which means 5 is multiplied by itself 3 times. So, 5^3 is equal to 5 x 5 x 5, which equals 125.
What is 64 in exponential form with 2 or 3 as the exponent?
Two to the sixth power. 8 with an exponent of 2 equals 64 and 4 with an exponent of 3 equals 64
What is the exponential form of 2187?
The exponential form of 2187 is 3^7. This is because 3 raised to the power of 7 equals 2187. In exponential form, the base (3) is raised to the power of the exponent (7) to give the result (2187).
Given that p equals log2q find an expression in terms of p for log2 routeq and log2 8q?
log2 sqrt(q) = p/2 log2 8q = 3 + p And it is root, not route.
How do we change from logarithmic form to exponential form?
Logb (x)=y is called the logarithmic form where logb means log with base b So to put this in exponential form we let b be the base and y the exponent by=x Here is an example log2 8=3 since 23 =8. In this case the term on the left is the logarithmic form while the one of the right is the exponential form.
What is exponential form of 6 cubed?
The exponential form of 6 cubed is 6^3. This means 6 multiplied by itself three times, which equals 216.
How do you solve log base 2 of x - 3 log base 2 of 5 equals 2 log base 2 of 10?
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
How do you solve log base 2 of 3 to the 1000?
log2(31000) = 1000 log2(3)log2(3) = 1.585 (rounded)1000 log2(3) = log2(31000) = 1,584.96(rounded)
What is the exponential form of 53?
The exponential form of 53 is 5^3. In exponential form, the base (5) is raised to the power of the exponent (3), which means 5 is multiplied by itself 3 times. So, 5^3 is equal to 5 x 5 x 5, which equals 125.
Log3 81 x log2 8 x log4 2 equals x?
log3 81 × log2 8 × log4 2 = log3 (33) × log2 (23) × log4 (40.5) = 3 × (log3 3) × 3 × (log2 2) × 0.5 × (log4 4) = 3 × 1 × 3 × 1 × 0.5 × 1 = 9 × 0.5 = 4.5
What is the exponential form for 96?
if you were paying attention in class you knew the answer
What is the exponential form of 3333?
The exponential form of 3333 is 3.333 x 10^3.
What is 64 in exponential form with 2 or 3 as the exponent?
Two to the sixth power. 8 with an exponent of 2 equals 64 and 4 with an exponent of 3 equals 64
What is 2x2x3x5x5x5 in exponential form?
2x2x3x5x5x5 in exponential form is: 22 x 3 x 53
