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Log(2) 8 =

log(2)2^(3) =

3log(2)2 =

3 x 1 = 3

NB Any number which has the same value as the log base equals 1.

Hence

log)a) a = 1

log(2)2 = 1

Hence

log(2)8 = 3

Antilog

8 = 2^(3)

Note the transposition of the numbers.

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lenpollock

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∙ 1w ago

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