Log(2) 8 =
log(2)2^(3) =
3log(2)2 =
3 x 1 = 3
NB Any number which has the same value as the log base equals 1.
Hence
log)a) a = 1
log(2)2 = 1
Hence
log(2)8 = 3
Antilog
8 = 2^(3)
Note the transposition of the numbers.
log2 sqrt(q) = p/2 log2 8q = 3 + p And it is root, not route.
Logb (x)=y is called the logarithmic form where logb means log with base b So to put this in exponential form we let b be the base and y the exponent by=x Here is an example log2 8=3 since 23 =8. In this case the term on the left is the logarithmic form while the one of the right is the exponential form.
The exponential form of 53 is 5^3. In exponential form, the base (5) is raised to the power of the exponent (3), which means 5 is multiplied by itself 3 times. So, 5^3 is equal to 5 x 5 x 5, which equals 125.
4 to the 2nd power that is the right answer promise
Two to the sixth power. 8 with an exponent of 2 equals 64 and 4 with an exponent of 3 equals 64
Since 2187is an ODD Number, try the lowest odd prime number '3'. Hence 3)2187 729 Keep on dividing by '3', until it will go no further, then try the next prime number '5'. Keep on doing this until you reduce to '1' . Hence 3)729 3)243 3)81 3)27 3)9 3)3 =1 Reduced to '1'. We have divided by '3' seven times over. Hence 2187 = 3^(7)_ The answer!!!!! NB Division by other prime numbers was not needed. NNB Use this 'step-ladder' system to find all the fctors/exponents of a given number.
log2 sqrt(q) = p/2 log2 8q = 3 + p And it is root, not route.
Logb (x)=y is called the logarithmic form where logb means log with base b So to put this in exponential form we let b be the base and y the exponent by=x Here is an example log2 8=3 since 23 =8. In this case the term on the left is the logarithmic form while the one of the right is the exponential form.
The exponential form of 6 cubed is 6^3. This means 6 multiplied by itself three times, which equals 216.
[log2 (x - 3)](log2 5) = 2log2 10 log2 (x - 3) = 2log2 10/log2 5 log2 (x - 3) = 2(log 10/log 2)/(log5/log 2) log2 (x - 3) = 2(log 10/log 5) log2 (x - 3) = 2(1/log 5) log2 (x - 3) = 2/log 5 x - 3 = 22/log x = 3 + 22/log 5
log3 81 × log2 8 × log4 2 = log3 (33) × log2 (23) × log4 (40.5) = 3 × (log3 3) × 3 × (log2 2) × 0.5 × (log4 4) = 3 × 1 × 3 × 1 × 0.5 × 1 = 9 × 0.5 = 4.5
The exponential form of 53 is 5^3. In exponential form, the base (5) is raised to the power of the exponent (3), which means 5 is multiplied by itself 3 times. So, 5^3 is equal to 5 x 5 x 5, which equals 125.
log2(31000) = 1000 log2(3)log2(3) = 1.585 (rounded)1000 log2(3) = log2(31000) = 1,584.96(rounded)
if you were paying attention in class you knew the answer
Two to the sixth power. 8 with an exponent of 2 equals 64 and 4 with an exponent of 3 equals 64
The exponential form of 3333 is 3.333 x 10^3.
2x2x3x5x5x5 in exponential form is: 22 x 3 x 53