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Well, isn't that just a happy little math question? When we say "m reduced by x," we are simply subtracting x from m. It's like taking away a few brushstrokes to reveal a new layer of the painting. Just remember, mistakes are just happy accidents waiting to be turned into something beautiful.
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What is the decimal multiplier to decrease by 11?
Suppose m is the required multiplier.Then multiplication by m would increase any x by 11, that is, x * m = x + 11 for all x x * m - x = 11 x*(m - 1) = 11 m - 1 = 11/x m = 1 + 11/x But that means that m is not defined for x = 0 and there is a different m for every non-zero x.
What is the number if M x M equals LY and then M x L equals YM?
m=8 l=6 y=4 m X m = 8 X 8 = 64 =ly m X l = 8 X 6 = 48 = ym
What is the answer to 15 m x 1000 m?
15 m x 1,000 m = 15,000 m2
What is the length and width of a bus?
There are various lengths of a bus and different types of buses. Type of bus - width - length School buses - 102 in x up to 45 ft. Greyhound - 9 ft x 45 ft Volve B10BLE - 2.4 m x 11.9 m Dennis Trident II - 2.5 m x 12 m Volvo B10TL - 2.5 m x 12 m Wheel-Chair Accessible bus - 2.5 m x 12 m Scania N113CRB - 2.5 x 11.9 m Mercedes-Benz 0.405 - 2.5 m x 11.6 m Volvo B10MA-60 - 2.5 m x 19 m Volvo Olympian - 2.4 m x 10.5 m Leyland Olympian 12 - 2.4 m x 12 m Leyland Atlantean AN 68 - 8 ft 1/2 in x 33 ft Mercedes-Benz 0.305 - 2.5 m x 10.6 m Volve B57 - 2.5 m x 11.9 m
How do you make x the subject of m equals n plus (x over p)?
If: m = n+x/p then x = p(m-n)
When chemical X is reduced which of these expressions would be an accurate representation of its reduced state?
The accurate expression for the reduced state of chemical X is X + electrons → X-. Here, X represents the oxidized form of chemical X, and X- represents the reduced form after gaining electrons.
What is a expression for x reduced by 5?
It is: x -5
What is the decimal multiplier to decrease by 11?
Suppose m is the required multiplier.Then multiplication by m would increase any x by 11, that is, x * m = x + 11 for all x x * m - x = 11 x*(m - 1) = 11 m - 1 = 11/x m = 1 + 11/x But that means that m is not defined for x = 0 and there is a different m for every non-zero x.
What is the number if M x M equals LY and then M x L equals YM?
m=8 l=6 y=4 m X m = 8 X 8 = 64 =ly m X l = 8 X 6 = 48 = ym
Why is 4 to the power 0 equal to 1?
for any non zero no. x, x^0=1 the proof is as follows, consider the two no.s x^m and x^n,where m and n are two non zero no.s. now let us assume without any oss of generality,that m>n,hence (x^m)/x^n=(x*x*x....m times)/(x*x*x...n times) now on the r.h.s, n no. of x in the denominator will cancel out n no. of x in the numerator(as x is non zero);leaving (m-n) no. of x in the numerator, i.e. (x^m)/(x^n)=x^(m-n) now letting m=n,we have x^m/x^m=x^(m-m) or, 1=x^0 hence the proof if x is also 0,i.e. 0 to the power 0 is undefined!
What are the instruction of ias computer?
InstructionTypeOpcodeSymbolicRepresentationDescriptionData transfer00001010000010010010000100000001000000100000001100000100LOAD MQLOAD MQ,M(X)STOR M(X)LOAD M(X)LOAD -M(X)LOAD |M(X)|LOAD -|M(X)|Transfer contents of register MQ to the accumulator ACTransfer contents of memory location X to MQTransfer contents of accumulator to memory location XTransfer M(X) to the accumulatorTransfer -M(X) to the accumulatorTransfer absolute value of M(X) to the accumulatorTransfer -|M(X)| to the accumulatorUnconditionalbranch0000110100001110JUMP M(X,0:19)JUMP M(X,20:39)Take next instruction from left half of M(X)Take next instruction from right half of M(X)Conditionalbranch0000111100010000JUMP+M(X,0:19)JUMP+M(X,20:39)If number in the accumulator is nonnegative, take next instruction from left half of M(X)If number in the accumulator is nonnegative , take next instruction from right half of M(X)Arithmetic0000010100000111000001100000100000001011000011000001010000010101ADD M(X)ADD |M(X)|SUB M(X)SUB |M(X)|MUL M(X)DIV M(X)LSHRSHAdd M(X) to AC; put the result in ACAdd |M(X)| to AC; put the result in ACSubtract M(X) from AC; put the result in ACSubtract |M(X)} from AC; put the remainder in ACMultiply M(X) by M(Q); put most significant bits of result in AC, put less significant bits in M(Q)Divide AC by M(X); put the quotient in MQ and the remainder in ACMultiply accumulator by 2 (i.e., shift left one bit position)Divide accumulator by 2 (i.e., shift right one bit position)Address modify0001001000010011STOR M(X,8:19)STOR M(X,28:39)Replace left address field at M(X) by 12 right-most bits of ACReplace right address field at M(X) by 12 right-most bits of AC
How do you find absolute deviation?
You do not have absolute deviation in isolation. Absolute deviation is usually defined around some measure of central tendency - usually the mean but it could be another measure. The absolute deviation of an observation x, about a measure m is |x - m| which is the non-negative value of (x - m). That is, |x - m| = x - m if x ≥ m and m - x if x < m
0.123 m x 12.31 m x 0.32 m?
0.123 x 12.31 x 0.32 = 0.4845216 m3
What is 9 m x 2.5 m?
9 m x 2.5 m = 22.5 m2.
What is the answer to 15 m x 1000 m?
15 m x 1,000 m = 15,000 m2
How many meter in 70 inches x50 inches?
1 in = 0.0254 m (exactly) ⇒ 70 in x 50 in = 70 x 0.0254 m x 50 x 0.0254 m = 1.778 m x 1.27 m
What are the law of exponent?
Exponents are subject to many laws, just like other mathematical properties. These are X^1 = X, X^0 = 1, X^-1 = 1/X, X^m * X^n = X^m+n, X^m/X^n = X^m-n, (X^m)^n = X^(m*n), (XY)^n = X^n * Y^n, (X/Y)^n = X^n/Y^n, and X^-n = 1/X^n.
