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What is m in this equation m times Parenthesis m minus 6 parenthesis equals 91?
m(m - 6) = 91 m(m) + m(-6) = 91 m2 - 6m = 91 subtract 91 from both sides m2 - 6m - 91 = 0 since -91 = (-13)(7) and -13 + 7 = -6, then (m + 7)(m - 13) = 0 m + 7 = 0 or m - 13 = 0 m = -7 or m = 13
What is the rule in adding integers?
The set of integers is closed under addition.Addition is commutative and associative. There exists a unique number, 0, such that n + 0 = 0 + n for any integer n. For every integer m, there exists an integer m' such that m + m' = m' + m = 0. m' is denoted by "-m".
What is 0 times 10?
It is: 0 times 10 = 0
What is 10293847560192837465 times 0?
10293847560192837465 times 0= 0
How do you solve m6 - 16m3 plus 64 equals 0?
m6 - 16m3 + 64 = 0 m6 - 8m3 - 8m3 + 64 = 0 m3(m3 - 8) - 8(m3 - 8) = 0 (m3 - 8)2 = 0 (m3 - 2m2 + 2m2 - 4m + 4m - 8)2 = 0 [m2(m-2) + 2m(m-2) + 4(m-2)]2 = 0 [(m2 +2m + 4)(m-2)]2 = 0 So m -2 = 0 or m2 + 2m + 4 = 0 ie m= 2 or m= -1 +/- i*sqrt(3) with each of the three roots being double roots.
7 from two times-m 0?
7
How do you solve 2-m times 0 plus -1?
It's gonna be -1. (2-m)*0 + (-1) = 0-1 = -1. Anything multiplied by 0 is 0 so that takes care of the (2-m)*0 and -1 is just -1. So -1 is the answer.
What is m in this equation m times Parenthesis m minus 6 parenthesis equals 91?
m(m - 6) = 91 m(m) + m(-6) = 91 m2 - 6m = 91 subtract 91 from both sides m2 - 6m - 91 = 0 since -91 = (-13)(7) and -13 + 7 = -6, then (m + 7)(m - 13) = 0 m + 7 = 0 or m - 13 = 0 m = -7 or m = 13
If one event has impossible outcomes and a second event has no possible outcomes after the first event has occurred then there are m times n total possible outcomes for the two events?
M=0 n=0 m*n=0
How man times must the number m be subtracted from m squared to give a restlt of zero?
Answer: 'm' times. Examples: If m=2, Then m2 = (2x2) = 4 -> 4-2-2 = 0 (So subtracted TWICE) If m=4 Then m2 = (4x4) = 16 -> 16-4-4-4-4 = 0 (So subtracted FOUR TIMES) This works no matter how large the number is!
Why is 4 to the power 0 equal to 1?
for any non zero no. x, x^0=1 the proof is as follows, consider the two no.s x^m and x^n,where m and n are two non zero no.s. now let us assume without any oss of generality,that m>n,hence (x^m)/x^n=(x*x*x....m times)/(x*x*x...n times) now on the r.h.s, n no. of x in the denominator will cancel out n no. of x in the numerator(as x is non zero);leaving (m-n) no. of x in the numerator, i.e. (x^m)/(x^n)=x^(m-n) now letting m=n,we have x^m/x^m=x^(m-m) or, 1=x^0 hence the proof if x is also 0,i.e. 0 to the power 0 is undefined!
Negative 6 plus m equals 0?
If: -6+m = 0 Then: m = 6
What is m if 0 equals -15m?
15
What is the rule in adding integers?
The set of integers is closed under addition.Addition is commutative and associative. There exists a unique number, 0, such that n + 0 = 0 + n for any integer n. For every integer m, there exists an integer m' such that m + m' = m' + m = 0. m' is denoted by "-m".
What is 3m squared minus 9m equal 0?
3m^2 - 9m = 0 factor out 3m 3m(m - 3) = 0 m = 0 -------- or m = 3 --------
How do you factor 0 equals 2m squared minus 2m plus 36?
0 = 2m^2 - 2m + 36 0 = 2(m^2 - m + 18) 0 = m^2 - m + 18
How do you slove m squared minus 8m equals -16?
24
