n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed
n3 - 93 can be factorised into (n - 9)(n2 + 9n + 81)
2 N cubed (3)
n2+n3=n5 it's simple 8th grade pre-algebra
Let the number be n.Then (n3)3 = n3 x 3 = n9.........or n to the power nine.However, if the question is what the the one-third power of a number cubed, then:(n3)1/3 = n3 x 1/3 = n1 = n
n squared x n n x n x n = n cubed n x n = n squared n squared x n = n cubed
"N cubed" refers to the mathematical operation of raising a number to the power of 3. This means multiplying the number by itself three times. For example, if n = 2, then n cubed would be 2 x 2 x 2, which equals 8. In general, n cubed can be represented as n^3 in mathematical notation.
n3 - 93 can be factorised into (n - 9)(n2 + 9n + 81)
n^3 (n cubed)
2 N cubed (3)
The sum of the first n cubed numbers is: [n*(n+1)/2]2 which is the same as the square of the sum of the first n numbers.
"n cubed" is not an algebra problem, since it asks no question. It's an "expression", whose numerical value depends on the value of ' n '.
. N times 6 cubed
It is n cubed.
6n5
Firstly to get 5n you times by 5!Next n3 (n cubed) is n x n x nTherefore you are timesing n by 5 and then by n and nSo 5n3 = times n by 5 x n x n or simplifyed n x 5n2
The sum of the first n cubed numbers is the square of the nth triangular number.