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If look for the pattern in these numbers, you can see that they follow a simple sequence in which each number is four more than the previous one. They are not multiples of four though, so they will have to be offset. In this case, that offset is two. This means that we can express this sequence as:

f(n) = 2 + 4n

assuming that 6 is the first term, with an "n" value of 1.

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15y ago

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james manolong

Lvl 2
4y ago

Bskwbsjsb

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Anonymous

Lvl 1
4y ago

6,10,14 and 18

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Anonymous

Lvl 1
4y ago

4

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Anonymous

Lvl 1
4y ago

6n+4

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Anonymous

Lvl 1
4y ago

N+4

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Anonymous

Lvl 1
4y ago

16

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Anonymous

Lvl 1
4y ago

17

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Anonymous

Lvl 1
4y ago

4n

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Anonymous

Lvl 1
4y ago

Four

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