perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
Yes, it can because a 3 by 6 rectangle has the perimeter of 18 and has the area of 18! :)
There is no standard relationship between perimeter and area. For example, you can have two rectangles that have the same perimeter, but different area.
Yes. Say there are two rectangles, both with perimeter of 20. One of the rectangles is a 2 by 8 rectangle. The area of this rectangle is 2 x 8 which is 16. The other rectangle is a 4 by 6 rectangle. It has an area of 4 x 6 which is 24.
This browser is hopeless for drawing but consider the following two rectangles: a*b and (a+1)*(b-1). Their perimeter will be 2a+2b but unless a = b-1, their area will be different.
There is an infinite number that can have that perimeter
10cm by 10cm (perimeter=40cm), 5cm by 20cm (perimeter=50cm), 50cm by 2cm (perimeter=104cm), 100cm by 1cm (perimeter=202cm). All of these rectangles' areas are 100cm2
they dont
perimeter = 2 (b+h) = 20 there are an infinite number of rectangles that meet the requirement
The perimeter of a rectangle is the sum of its four sides. Add the sides for both rectangles, then compare the results.
area = 144 square units perimeter = 48 units
No rectangle can have equal perimeter and length.
There would be an infinite number of rectangles possible
thare is only 1 differint rectangles
No
2l+2w
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