...if you did not recognize this to be (x - 1)^2... x^2 - 2x + 1 = 0 or x^2 - x - x + 1 = 0 x(x - 1) - 1(x -1) = 0 (x - 1) (x - 1) = 0 x = 1
| x | y | x' | y' | x⊕y | x'⊕y' | ---------------------------------- | 0 | 0 | 1 | 1 | 0 | 0 | | 0 | 1 | 1 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 0 | 0 |
2 x 0 x 1 + 1 = 0 + 1 = 1
16x³ - x = 0 By factorization, we obtain: x(16x² - 1) = 0 x(4x - 1)(4x + 1) = 0 Set each term by 0 and solve for x to get: x = 0 and 4x - 1 = 0 and 4x + 1 = 0 x = {0, ±¼}
Either of these ways is correct:(1 x 109) + (4 x 108) + (1 x 107) + (3 x 106) + (0 x 105) + (0 x 104) + (1 x 103) + (0 x 102) + (0 x 101) + (0 x 100).(1 x 1000000000) + (4 x 100000000) + (1 x 10000000) + (3 x 1000000) + (0 x 100000) + (0 x 10000) + (1 x 1000) + (0 x 100) + (0 x 10) + (0 x 1).
...if you did not recognize this to be (x - 1)^2... x^2 - 2x + 1 = 0 or x^2 - x - x + 1 = 0 x(x - 1) - 1(x -1) = 0 (x - 1) (x - 1) = 0 x = 1
| x | y | x' | y' | x⊕y | x'⊕y' | ---------------------------------- | 0 | 0 | 1 | 1 | 0 | 0 | | 0 | 1 | 1 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 0 | 0 |
| x | y | x' | y' | x⊕y | x'⊕y' | ---------------------------------- | 0 | 0 | 1 | 1 | 0 | 0 | | 0 | 1 | 1 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 0 | 0 |
X + 1 - x - 1 = 0, for all x. Regroup: (x - x) + (1 - 1) = 0 + 0.
x is equals to 0 or 1. How is it solved? .... x.x =x x.x - x = 0 which can be solved by the usual formula for quadratic equations, or.. x.(x-1)=0 x= 0 or x-1 =0 x=0 or x=1
2 x 0 x 1 + 1 = 0 + 1 = 1
16x³ - x = 0 By factorization, we obtain: x(16x² - 1) = 0 x(4x - 1)(4x + 1) = 0 Set each term by 0 and solve for x to get: x = 0 and 4x - 1 = 0 and 4x + 1 = 0 x = {0, ±¼}
x^2 + 1 = 0 x^2 - (-1) = 0 x^2 - i^2 = 0 (x - i)(x + i) = 0 x = i or x = -i
Either of these ways is correct:(1 x 109) + (4 x 108) + (1 x 107) + (3 x 106) + (0 x 105) + (0 x 104) + (1 x 103) + (0 x 102) + (0 x 101) + (0 x 100).(1 x 1000000000) + (4 x 100000000) + (1 x 10000000) + (3 x 1000000) + (0 x 100000) + (0 x 10000) + (1 x 1000) + (0 x 100) + (0 x 10) + (0 x 1).
Any number to the power of zero is 1, because if you raise x^0 by a power (in other words, if you multiply x^0 by x), you should get x^1, which is the same as x. and 1 times x is always equal to x, so x^0=1 1^0=1 2^0=1 7283423592348324236^0=1 x^0=1 You figure out what 40^0 is...
One 0 and 1 0 X 0 = 0 1 X 1 = 1Only positive 1 though.Negative 1 will produce the answer of a positive 1.Solve x = x^2x^2 - x = 0x ( x - 1 ) = 0Has solutions x=0 and x=1
1,000,102,200 = (1 x 1000000000) + (0 x 100000000) + (0 x 10000000) + (0 x 1000000) + (1 x 100000) + (0 x 10000) + (2 x 1000) + (2 x 100) + (0 x 10) + (0 x 1)or(1 x 109) + (0 x 108) + (0 x 107) + (0 x 106) + (1 x 105) + (0 x 104) + (2 x 103) + (2 x 102) + (0 x 101) + (0 x 100)