1 × 0 = 0
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...if you did not recognize this to be (x - 1)^2... x^2 - 2x + 1 = 0 or x^2 - x - x + 1 = 0 x(x - 1) - 1(x -1) = 0 (x - 1) (x - 1) = 0 x = 1
| x | y | x' | y' | x⊕y | x'⊕y' | ---------------------------------- | 0 | 0 | 1 | 1 | 0 | 0 | | 0 | 1 | 1 | 0 | 1 | 1 | | 1 | 0 | 0 | 1 | 1 | 1 | | 1 | 1 | 0 | 0 | 0 | 0 |
2 x 0 x 1 + 1 = 0 + 1 = 1
16x³ - x = 0 By factorization, we obtain: x(16x² - 1) = 0 x(4x - 1)(4x + 1) = 0 Set each term by 0 and solve for x to get: x = 0 and 4x - 1 = 0 and 4x + 1 = 0 x = {0, ±¼}
Either of these ways is correct:(1 x 109) + (4 x 108) + (1 x 107) + (3 x 106) + (0 x 105) + (0 x 104) + (1 x 103) + (0 x 102) + (0 x 101) + (0 x 100).(1 x 1000000000) + (4 x 100000000) + (1 x 10000000) + (3 x 1000000) + (0 x 100000) + (0 x 10000) + (1 x 1000) + (0 x 100) + (0 x 10) + (0 x 1).