2n+4: 6,8,10......104........204
4n
7+2n
6n -3=2n+9 6n-2n=9+3 4n=12 n=12/4 n=3
That factors to (2n + 1)(n + 2)
2n plus 4 = 2n + 4
You can't. 17 + 2n = 21 + 2n gives: 2n = 4 + 2n which gives 0=4 which is not possible so the sum is not solveable.
It's an algbraic expession in the form of: 2n+4
-3n+5n+4 = -4 2n = -4-4 2n = -8 n = -4
'n' can be any number, but when applied to (2n + 4), n = 2.5
The sum of the numbers given is 31. 1 + 2 + 4 + 8 + ... + 2n = 2n+1 - 1
10n = 7n + 4 + 2n so 10n = 9n + 4 Subtract 9n from both sides: n = 4
5n + 7 = 28 + 2n (-2n) 3n + 7 = 28 (-7) 3n = 21 therefore, n = 7
2n + 4m - 2n + m = 5m
2n+4: 6,8,10......104........204
1 + 2 + 4 + ... + 2n = 2n+1 - 1
n = 1