The length of the other diagonal works out as 12cm
Constructing the figure, we find the other diagonal to have length 10.The area of the rhombus would thus be 10x8x0.5=40
It is a rhombus or a kite
There is no relationship between the perimeter and the area of a rhombus. Take a rhombus with all 4 sides = 2 units. Therefore the perimeter is 8 units. There are an infinite number of possible areas for this rhombus. The largest possible area will be when the rhombus approaches the shape of a square = 4 square units. The smallest area will be when the one diagonal approaches 0 units and the other diagonal approaches 4 units (squashed almost flat). So two very extreme areas can have the same perimeter, including all those areas in-between.
The length of the sides of the rhombus are 10cm, as a rhombus has equal sides. since the diagonals of a rhombus are perpendicular, ratio of side of rhombus to 1/2 a diagonal to 1/2 of another diagonal is 5:4:3 (pythagorean thriple), hence ratio of side of rhombus to 1 diagonal to another diagonal is 5:8:6. since 5 units = 10cm 8 units = 16cm 6 units = 12cm and there are your diagonals.
The perimeter of a square with a diagonal of 12 centimeters is: 33.9 centimeters.In future, to find out the perimeter of a square when you only know it's diagonal, use Pythagoras or times the diagonal by 2.828427125.This number is irrational, and is like a pi for the diagonals of squares.I call it Tau.It is the relationship between the diagonal of all squares and there perimeter.
Perimeter = 4*Side so that Side = Perimeter/4 Area of a rhombus = Side * Altitude so Altitude = Area/Side = Area/(Perimeter/4) = 4*Area/Perimeter
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
Rhombus Area = side x height = 6 cm x 4 cm = 24 cm2In the right triangle formed by the side and the height of the rhombus, we have:sin (angle opposite to the height) = height/side = 4 cm/6cm = 2/3, so thatthe angle measure = sin-1 (2/3) ≈ 41.8⁰.In the triangle formed by two adjacent sides and the required diagonal, which is opposite to the angle of 41.8⁰ of the rhombus, we have: (use the Law of Cosines)diagonal length = √[62 + 62 -2(6)(6)cos 41.8⁰] ≈ 4.3Thus, the length of the other diagonal of the rhombus is about 4.3 cm long.
If side is given too, then you can find area with one diagonal. As diagonals bisect each other in a rhombus at 90°, Using Pythogoras Theorem: (Half d1)² = (side)² - (Half d2)²
All the 4 sides of a rhombus are equal, so 4 times the length of a side.
To find the perimeter of a square with a diagonal of 16 cm, we first need to determine the side length of the square using the Pythagorean theorem. The diagonal of a square divides it into two right-angled triangles, with the diagonal being the hypotenuse. Using the formula a^2 + b^2 = c^2, where a and b are the two sides of the triangle and c is the hypotenuse, we can calculate that each side of the square is 8β2 cm. Since a square has four equal sides, the perimeter is 4 times the side length, giving us a perimeter of 32β2 cm.