In 6 hours @ 120 km per hour, the train travels 120*6 = 720 km.
In 5 hours @ 100 km per hour, the train travels 100*5 = 500 km.
So, in all the train travels 720 + 500 = 1220 km in 6 + 5 = 11 hours.
Its average speed is 1220/11 =110.9090.. recurring km per hour.
The train travels at 123.7 km/h
Average speed = Total Distance/Total Time = 350/3 = 116.66... km per hour.
Speed = Distance/Time = 100 km / 4 hours = 100/4 km per hour = 25 kph
131.82 miles per hour.
370 km/ 87 hours ~= 4.25 km/hr
The train travels at 123.7 km/h
454 km
Average speed = Total Distance/Total Time = 350/3 = 116.66... km per hour.
This is an average speed of 42.54 km/h
a high speed train travels south for 2.00 h for a distance of 454km. what is its average velocity?
To find the average speed of the train, divide the distance traveled (in kilometers) by the time taken (in hours). The formula is: Average Speed = Distance / Time. Therefore, if the train traveled ( km ) in ( w ) hours, its average speed would be ( \frac{km}{w} ) kilometers per hour.
Just multiply the 45 hours by the speed.
39 miles
Speed = Distance/Time = 100 km / 4 hours = 100/4 km per hour = 25 kph
131.82 miles per hour.
Hints: speed = (distance) / (time) You need to convert 1 hour + 45 minutes into a single unit, such as hours or minutes.
The train's average speed was 34.5 miles per hour.