Assume the expression is:
x² + y² - 10x = 0
Complete the squares to get:
(x² - 10x + 25) + y² = 25
(x - 5)² + y² = 25
So by using this form:
(x - h)² + (y - k)² = r² where
(h,k) = center
r = radius
We obtain the center of (5,0) for this expression:
(x - 5)² + (y - 0)² = 5²
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
x2+y2+4x+2y+3=0(x+2)2 + (Y+2.5)2 = 3This is the equation of circle with center at (-2,-2.5) with radius 3.5
That's the equation of a circle with its center at the origin and a radius of 8.
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
4
Without an equality sign it can't be considered to be an equation but in general the equation of a circle whose centre is at (a, b) and radius is r is:- (x-a)^2+(y-b)^2 = r^2
The center of the circle is at (9, 7) on the Cartesian plane
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
56
If that means = 36 then then the radius of the circle is 6 units
The center of the circle is at (-7, 5)
(-5,3)
At the center, (x, y) = (-2, 5)
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
Without an equality sign the given terms can't be considered to be the equation of a circle.
(-7,5)
(-4,3)