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Need math homework help x2 plus y2 plus 10x plus 2y plus 22 equals 0 i am looking for the graph of the equation is a circle with a center and the radius?
We have: x^2 + y^2 + 10x + 2y + 22 = 0 We want to find the standard equation for a circle, which is: (x - a)^2 + (y - b)^2 = r^2 Where (a,b) is the center of the circle, and the radius is r. Regroup with like variables, and move the constant term to the right: x^2 + 10x + y^2 + 2y = -22 complete the square on both quadratics on the left: x^2 + 10x + c + y^2 + 2y + d = -22 + c + d find c, such that 2 * (c^(1/2)) = 10 and find d, such that 2 * (d^(1/2)) = 2 c = 25 d = 1 x^2 + 10x + 25 + y^2 + 2y + 1 = -22 + 25 + 1 (x + 5)^2 + (y + 1)^2 = 4 We now have the standard equation for a circle, which gives us a center at: (-5, -1) and which has a radius of 2.
What is the diameter of a 22 circumference circle?
The diameter of a 22 circumference circle is: 7
What is the standard equation of the parabola y3(x-4)2-22?
the standard form of the equation of a parabola is x=y2+10y+22
What is the diameter of a circle with a radius of 11cm?
22
What is 4h-6 equals 22?
It is an equation and if 4h-6 = 22 then h = 7
What is the center of the circle given that the equation is x - 9 2 plus y 2 equals 484?
(x-9)2 + y2 = 484The center is atx = 9y = 0The radius of the circle is 22 .
Is the given point interior exterior or on the circle x 22 y - 32 81?
To determine if the point (22, -32) is interior, exterior, or on the circle defined by the equation (x^2 + y^2 = 81), we first calculate the distance from the point to the center of the circle, which is at the origin (0, 0). The distance is given by (d = \sqrt{22^2 + (-32)^2} = \sqrt{484 + 1024} = \sqrt{1508} \approx 38.8). Since the radius of the circle is 9 (since (81 = 9^2)), and (38.8) is greater than (9), the point (22, -32) is located outside the circle.
What is a result of shifting a circle with equation x 32 y - 22 36 left 3 units?
Shifting the circle with the equation ( x^2 + y^2 - 22x - 36 = 0 ) left by 3 units involves adjusting the ( x ) coordinate in the equation. The new equation becomes ( (x + 3)^2 + y^2 - 22(x + 3) - 36 = 0 ). This results in a new center for the circle, which is now located at ( (19, 0) ) instead of ( (22, 0) ), while the radius remains unchanged. Thus, the overall shape and size of the circle do not change, only its position.
How do you calculate circumference of a circle using fractions as pi?
Pi is 22/7. Therefore, the equation for finding the circumference of a circle using fractions is: 22/7 mutiplied by the diameter of the circle :)
What is the equation for finding the circumfrence of a circle?
2*pi*radius of the circle or diameter*pi where pi = 3.1416 or 22/7 and is usually rounded to 3.14.
How many feet across is a 22 ft diameter circle?
22 ft. The diameter is the measurement of a circle through the center from side to side and is equal to two times the radius.
When a body moves along a semicircle total angle subtended by it at centre of circle is?
Pie/2=22/7/2Angle in radians =Total length of the arc/radius of the circle
What is the slope of the line given by the equation y5x-22?
27
What is the equation of a circle with center 1and 5 and radius 2?
A circle with centre (xo, yo) and radius r has formula: (x - xo)2 + (y - yo)2 = r2 For circle with centre (1, 5) and radius 2 this is: (x - 1)2 + (y - 5)2 = 22 x2 - 2x + 1 +y2 - 10y + 25 = 4 x2 - 2x + y2 - 10y + 22 = 0
Which is the equation of a circle that passes through 22 and is centered at 56?
Radius of the circle is sqrt*[(5-2)2 + (6-2)2] = 5 So the equation is (x - 5)2 + (y - 6)2 = 25
Need math homework help x2 plus y2 plus 10x plus 2y plus 22 equals 0 i am looking for the graph of the equation is a circle with a center and the radius?
We have: x^2 + y^2 + 10x + 2y + 22 = 0 We want to find the standard equation for a circle, which is: (x - a)^2 + (y - b)^2 = r^2 Where (a,b) is the center of the circle, and the radius is r. Regroup with like variables, and move the constant term to the right: x^2 + 10x + y^2 + 2y = -22 complete the square on both quadratics on the left: x^2 + 10x + c + y^2 + 2y + d = -22 + c + d find c, such that 2 * (c^(1/2)) = 10 and find d, such that 2 * (d^(1/2)) = 2 c = 25 d = 1 x^2 + 10x + 25 + y^2 + 2y + 1 = -22 + 25 + 1 (x + 5)^2 + (y + 1)^2 = 4 We now have the standard equation for a circle, which gives us a center at: (-5, -1) and which has a radius of 2.
What is the slope intercept equation for (-22 -14) and (-18 -12)?
Not enough information has been given because in order to work out a straight line equation the slope and coordinates of (x, y) must be given
