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The cross-sectional area of a pipe can be calculated using the formula for the area of a circle, A = πr^2, where r is the radius of the pipe. Since the diameter of the pipe is given as 4 inches, the radius would be half of the diameter, so r = 2 inches. Plugging this value into the formula, we get A = π(2)^2 = 4π square inches. Therefore, the cross-sectional area of the 4-inch pipe is 4π square inches.

Q: What is the cross sectional area of the 4 inch pipe?

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8 inch schedule 40 pipe has a cross sectional area of 0.0583 square feet

Method to find area of a circle is: The area of a circle is its radius squared times pi. Assuming the pipe has a diameter of 4cm: radius = 2 cm Circumference = 12.5664 cm Area = 12.5664 cm2

The answer depends on the cross section of the pipe and its length.

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Cross-sectional area of pipe is π(1.5)² = 7.07 cm² that means the flow is 10 cm/s x 7.07 cm² = 70.7 cm³/s 70.7 cm³/s x 60 sec = 4240 cm³ or 4.24 Liter

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8 inch schedule 40 pipe has a cross sectional area of 0.0583 square feet

It depends on what you mean by a 30 pipe. Is 30 the cross sectional area - in which case, what is the length of the pipe? Is 30 the length - in which case, what is the cross-sectional area?

It would take sixteen one-inch pipes to equal the cross-sectional area of one four-inch pipe. This assumes the pipes are circular in cross-section.

It's not likely that any property of fluids correlates in any way with any Vatican situation. If a pipe of X cross sectional area is connected so a fluid flows at a specific velocity, and then a pipe of 2X cross sectional area is connected to the pipe of X cross sectional area, the velocity of fluid flowing in the 2X pipe will be less than what is flowing in the X pipe. In this case, what you're saying is true.

The average velocity of water in a pipe depends on the flow rate of the water and the cross-sectional area of the pipe. It can be calculated by dividing the flow rate by the cross-sectional area. The units are typically expressed in meters per second.

It depends on the cross sectional area of the pipe.

To start, we will find the cross sectional area of the pipes. Pipe with radius of 2 inches Cross sectional area = PI x radius2 = 12.56 inches2 Pipe with radius of 3 inches Cross sectional area = PI x radius2 = 28.26 inches2 Pipe with radius of 5 inches Cross sectional area = PI x radius2 = 78.5 inches2 As the cross sectional area of the pipe with a radius of 5 inches (78.5 inches2) is greater than the sum of the cross sectional areas of the pipes with radii of 2 inches and 3 inches (40.82 inches2), it can be concluded that the pipe with a radius of 5 inches will be able to carry the most water. (Assuming that all three pipes are the same length).

It all depends upon the shape of the container that it is in. For example, if the water weighs 8 lbs per gallon, then the water at the bottom of a container that is a vertical pipe with cross sectional area of 1 square inch will exert a pressure of 8 psi. However, if the water is in a vertical pipe with cross sectional area of 8 square inches, then the pressure at the bottom of the pipe will be only 1 psi.

It's not supposed to change. If the cross-sectional area does change through a bend, then the pipe is said to be "kinked". The bend is regarded as poorly done, and if the kink is deep enough, the section of pipe including the bend may have to be replaced.

7.07 square feet

To calculate air velocity in a pipe, you would need to measure either the volumetric flow rate or the mass flow rate of air flowing through the pipe. You can then use the formula: air velocity = volumetric flow rate / cross-sectional area of the pipe, or air velocity = mass flow rate / (density of air * cross-sectional area of the pipe).

To calculate the volume of the pipe, we first need to determine the cross-sectional area using the formula A = πr^2, where r is the radius (4 inches). Then, multiply the cross-sectional area by the length of the pipe to find the volume in cubic inches. Finally, convert the volume from cubic inches to cubic feet by dividing by 1728.