The cross-sectional area of a pipe can be calculated using the formula for the area of a circle, A = πr^2, where r is the radius of the pipe. Since the diameter of the pipe is given as 4 inches, the radius would be half of the diameter, so r = 2 inches. Plugging this value into the formula, we get A = π(2)^2 = 4π square inches. Therefore, the cross-sectional area of the 4-inch pipe is 4π square inches.
I assume you mean 1 and 3/4 inches in diameter. Therefore your cross-sectional area of your hose is pi/4*diameter. You can either leave your diameter in inches or convert it to feet. If you choose to leave you number in inches then you convert 100 ft to 1200 in and multiple 1200*cross-sectional area to get the cubic inches water in the hose. If you choose to convert your diameter to feet then just multiply 100 ft times cross-sectional area to get the cubic ft of water in the hose.
The surface area of a prism is twice the area of the end plus the area of all the sides. For a prism with a polygon cross-section the area of all the sides if given by the perimeter of the cross-section polygon multiplied by the length of the prism. Assuming you have a prism of cross-section that is a rectangle with sides 4 mm and 3 mm, and is 15 mm long (ie it is an oblong), its surface area is: → surface_area = 2 × (4 mm × 3 mm) + 2 × (4 mm + 3 mm) × 15 mm → surface area = 2 × 12 mm² + 14 mm × 15 mm = 234 mm²
Area = pi x radius^2 Multiply that answer by 30feet and you have the volume of the pipe.
A prism must have a minimum of 4 lengths: three (or more) for the cross section and one for the length. There can be fewer cross-sectional measures if more is known about it: for example, one measure would be enough for a regular polygon (you'd need to know how many sides). But there is no such supplementary information.
It depends on the cross sectional area of the pipe.
The cross-sectional area of a pipe can be calculated using the formula for the area of a circle, A = πr^2, where r is the radius of the pipe. Since the diameter of the pipe is given as 4 inches, the radius would be half of the diameter, so r = 2 inches. Plugging this value into the formula, we get A = π(2)^2 = 4π square inches. Therefore, the cross-sectional area of the 4-inch pipe is 4π square inches.
To calculate the volume of the pipe, we first need to determine the cross-sectional area using the formula A = πr^2, where r is the radius (4 inches). Then, multiply the cross-sectional area by the length of the pipe to find the volume in cubic inches. Finally, convert the volume from cubic inches to cubic feet by dividing by 1728.
An equilateral 1 inch triangle is a plane figure and it does not have a cross-sectional area in any meaningful sense, just an area. Its area is 0.43 = sqrt(3)/4 square inches.
Area of cross section of wire= Pi X D2/4=3.14 X (0.0625)2/4=0.0031
0.1631168The value 0.1631168 is the number of US gallons per foot of 2" pipe. The number of gallons per foot of 4" pipe is 0.652798
When you double the radius of a copper wire, you increase its cross-sectional area by a factor of 4. Since resistance is inversely proportional to the cross-sectional area, the resistance decreases by a factor of 4. This relationship is described by the formula R = ρL/A, where R is resistance, ρ is resistivity, L is length, and A is cross-sectional area.
The volume of a rod can be calculated by multiplying the cross-sectional area of the rod by its length. The formula to calculate the volume of a rod is V = A x L, where V is the volume, A is the cross-sectional area, and L is the length of the rod.
Assuming the pipe is 100% full, find the cross sectional area of the pipe & multiply by length to get volume:CA = (Pi/4)*(diameter2) = (Pi/4)*(0.667 ft)2CA = 0.349 ft2Volume = (CA)*(Length) = 0.349 ft2 * 20 ft = 6.99 ft31 ft3 = 7.4805 gallonsSo, 6.99 * 7.4805 = 52.29 gallons
Usually it means a piece of wood/lumber that has a cross-sectional area of 4 square inches, meaning that the cross section is a square of 2 inch side.
Assuming the pipe is 100% full then the volume will be the cross sectional area of the pipe times length. Vol = Pi/4 * (diameter)2 * (length) = (3.14/4)*(0.1 m)2*(1 m) Volume is approximately 0.008 m3. 1 cubic meter is 1000 liters so the volume would be about 8 liters.
The hydraulic diameter for any cross section is: Dh= 4 * A / Wp Where Dh = hydraulic diameter A = cross sectional area Wp = wetted perimeter