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What is the cross sectional area of the 4 inch pipe?
The cross-sectional area of a pipe can be calculated using the formula for the area of a circle, A = πr^2, where r is the radius of the pipe. Since the diameter of the pipe is given as 4 inches, the radius would be half of the diameter, so r = 2 inches. Plugging this value into the formula, we get A = π(2)^2 = 4π square inches. Therefore, the cross-sectional area of the 4-inch pipe is 4π square inches.
How much water does a hose carry that is one and 34 inches in diameter times 100 feet?
I assume you mean 1 and 3/4 inches in diameter. Therefore your cross-sectional area of your hose is pi/4*diameter. You can either leave your diameter in inches or convert it to feet. If you choose to leave you number in inches then you convert 100 ft to 1200 in and multiple 1200*cross-sectional area to get the cubic inches water in the hose. If you choose to convert your diameter to feet then just multiply 100 ft times cross-sectional area to get the cubic ft of water in the hose.
What is the surface area of a prism with a length of 15mm a height of 4 mm and a width of 3mm?
The surface area of a prism is twice the area of the end plus the area of all the sides. For a prism with a polygon cross-section the area of all the sides if given by the perimeter of the cross-section polygon multiplied by the length of the prism. Assuming you have a prism of cross-section that is a rectangle with sides 4 mm and 3 mm, and is 15 mm long (ie it is an oblong), its surface area is: → surface_area = 2 × (4 mm × 3 mm) + 2 × (4 mm + 3 mm) × 15 mm → surface area = 2 × 12 mm² + 14 mm × 15 mm = 234 mm²
How many gallons of water does a 4 in pipe hold per 30 feet?
Area = pi x radius^2 Multiply that answer by 30feet and you have the volume of the pipe.
What is the volume of a prism whose dimensions are 2cm3cm2cm?
A prism must have a minimum of 4 lengths: three (or more) for the cross section and one for the length. There can be fewer cross-sectional measures if more is known about it: for example, one measure would be enough for a regular polygon (you'd need to know how many sides). But there is no such supplementary information.
