100
1100
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I can't say for certain what your specific difficulty is with the process, so I will guess unfamiliarity. There are many fine websites that will perform those calculations automatically.------------------------------There is a general method to convert from base 10 to any other base:divide the number by the base to get a whole number quotient and remaindernote the remainderreplace the number by the quotientif the number is not zero repeat from step 1write the remainders in reverse order to get the decimal number in the new base.With this converting a decimal number to binary is quite straight forward; for example 205 in binary:205 ÷ 2 = 102 r 1102 ÷ 2 = 51 r 051 ÷ 2 = 25 r 125 ÷ 2 = 12 r 112 ÷ 2 = 6 r 06 ÷ 2 = 3 r 03 ÷ 2 = 1 r 11 ÷ 2 = 0 r 1→ 205 in decimal is 1100 1101 in binary.What you may be complaining about is that converting octal and hexadecimal numbers to binary is extremely straight forward and direct; examples:0315 (octal) = 11 001 101 = 1100 1101 in binary0xcd (hexadecimal) = 1100 1101 binaryThese conversions are extremely easy as each digit of an octal or hexadecimal number uses an exact number of binary digits:octal numbers 0-7 are the fill range of the binary numbers 000-111 - 3 binary digitshexadecimal numbers 0-f are the full range of the binary numbers 0000-1111 - 4 binary digits.There is no waste so each digit of an octal or hexadecimal number can be converted into binary directly. Each new octal or hexadecimal place value column is represented by an exact 3 or 4 block of binary digits, so when a place value is added, another block of binary digits is added, so 07 + 01 = 010 which in binary is 111 + 001 = 001 000; similarly 0xf + 0x1 = 0x10 which in binary is 1111 + 0001 = 0001 0000With decimal numbers, however, the digits 0-9 are represented by the binary 0000-1001; if each digit of a decimal number was converted to binary (an encoding known as Binary Coded Decimal, or BCD) then the binary numbers 1010-1111 (6 of them) are not being used and wasted. Alternatively, when a new place value is needed in decimal the binary will still likely use the binary digits already being used without the need for an extra block, eg 9 + 1 = 10 which in binary is 1001 + 0001 = 1010; there is no 1:1 correspondence between blocks of binary digits and decimal digits that occurs with octal and hexadecimal numbers.
1010 1100
1100
9: 1001 10: 1010 11: 1011 12: 1100 13: 1101 14: 1110 15: 1111 16: 10000
110010010001 is 3217 in decimal.
100
0xc = 1100 Hexadecimal digits use exactly 4 binary digits (bits). The 0x0 to 0xf of hexadecimal map to 0000 to 1111 of binary. Thinking of the hexadecimal digits as decimal numbers, ie 0x0 to 0x9 are 0 to 9 and 0xa to 0xf are 10 to 15, helps with the conversion to binary: 0xc is 12 decimal which is 8 + 4 → 1100 in [4 bit] binary.
12 in binary would be 1100
1100
1110 0111 1100 00112 is not a binary number as it has three different symbols
In BCD each digit of a decimal number is coded as a separate 4 bit binary number between 0 and 9.For example:Decimal 12 in BCD is shown as 0001 0010 (Binary 1 and Binary 2), in Binary it is 1100.
The answer is 1100.
It is 1100.
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