1100
THIS MY FINAL ANSWER IT WAS A MISTAKE AT FIRST 1 = 0110000 2= 110110
1100000 110110
12
111111112 = 1000000002 - 12 = [in decimal] 28 - 1 = 64 - 1 = 63
I can't say for certain what your specific difficulty is with the process, so I will guess unfamiliarity. There are many fine websites that will perform those calculations automatically.------------------------------There is a general method to convert from base 10 to any other base:divide the number by the base to get a whole number quotient and remaindernote the remainderreplace the number by the quotientif the number is not zero repeat from step 1write the remainders in reverse order to get the decimal number in the new base.With this converting a decimal number to binary is quite straight forward; for example 205 in binary:205 ÷ 2 = 102 r 1102 ÷ 2 = 51 r 051 ÷ 2 = 25 r 125 ÷ 2 = 12 r 112 ÷ 2 = 6 r 06 ÷ 2 = 3 r 03 ÷ 2 = 1 r 11 ÷ 2 = 0 r 1→ 205 in decimal is 1100 1101 in binary.What you may be complaining about is that converting octal and hexadecimal numbers to binary is extremely straight forward and direct; examples:0315 (octal) = 11 001 101 = 1100 1101 in binary0xcd (hexadecimal) = 1100 1101 binaryThese conversions are extremely easy as each digit of an octal or hexadecimal number uses an exact number of binary digits:octal numbers 0-7 are the fill range of the binary numbers 000-111 - 3 binary digitshexadecimal numbers 0-f are the full range of the binary numbers 0000-1111 - 4 binary digits.There is no waste so each digit of an octal or hexadecimal number can be converted into binary directly. Each new octal or hexadecimal place value column is represented by an exact 3 or 4 block of binary digits, so when a place value is added, another block of binary digits is added, so 07 + 01 = 010 which in binary is 111 + 001 = 001 000; similarly 0xf + 0x1 = 0x10 which in binary is 1111 + 0001 = 0001 0000With decimal numbers, however, the digits 0-9 are represented by the binary 0000-1001; if each digit of a decimal number was converted to binary (an encoding known as Binary Coded Decimal, or BCD) then the binary numbers 1010-1111 (6 of them) are not being used and wasted. Alternatively, when a new place value is needed in decimal the binary will still likely use the binary digits already being used without the need for an extra block, eg 9 + 1 = 10 which in binary is 1001 + 0001 = 1010; there is no 1:1 correspondence between blocks of binary digits and decimal digits that occurs with octal and hexadecimal numbers.
12/5 = 1.4 when expressed as a decimal number.
12 centimeters =
12
1100
111111112 = 1000000002 - 12 = [in decimal] 28 - 1 = 64 - 1 = 63
The Binary code represents all data in 0s and 1s by using a combination of these. Each number system and digital data like characters and other symbols can be represented in binary by a common conversion method for each system. Example: Decimal number 12 is binary number 1100. this is obtained as [1*(2^3) + 1*(2^2) + 0*(2^1) + 0*(2^0)]
In BCD each digit of a decimal number is coded as a separate 4 bit binary number between 0 and 9.For example:Decimal 12 in BCD is shown as 0001 0010 (Binary 1 and Binary 2), in Binary it is 1100.
12 in binary would be 1100
9: 1001 10: 1010 11: 1011 12: 1100 13: 1101 14: 1110 15: 1111 16: 10000
BCD, which stands for Binary Coded Decimal. 4 bits are used to code each decimal digit. So we have 0000 for zero, up to 0111 for seven, then 1000 for eight and 1001 for nine. The others {ten through fifteen} are not used, as those numbers are formed from additional decimal digits. So if you wanted to form twelve, in BCD it is 0001 0010, for 12{base ten}
0xc = 1100 Hexadecimal digits use exactly 4 binary digits (bits). The 0x0 to 0xf of hexadecimal map to 0000 to 1111 of binary. Thinking of the hexadecimal digits as decimal numbers, ie 0x0 to 0x9 are 0 to 9 and 0xa to 0xf are 10 to 15, helps with the conversion to binary: 0xc is 12 decimal which is 8 + 4 → 1100 in [4 bit] binary.
If you mean a straight forward algorithm, then yes.I guess you want to know what it is...Start at the left hand end of the binary number with the result (decimal number) set to zerodouble the result and add the current binary digitif there are more binary digits move one binary digit to the right and repeat step 2repeat steps 2 and 3 until all the binary digits have been used.the result is the decimal equivalentfor example converting 101002 to decimal:1. set result to 0, start with the first binary digit (of 10100) which is 12. 2 x 0 + 1 = 13. 2nd binary digit (of 10100) is 02. 2 x 1 + 0 = 23. 3rd binary digit (of 10100) is 12. 2 x 2 + 1 = 53. 4th binary digit (of 10100) is 02. 2 x 5 + 0 = 103. 5th binary digit (of 10100) is 02. 2 x 10 + 0 = 203. no more binary digits4. 101002 = 2010
To convert decimal to binary, divide the decimal number you want to convert by 2 and write down the remainder. Repeat this until the final result is zero. The remainders you wrote down, written from the last one you wrote to the first (so the opposite order from which you derived them) is the binary equivalent.So using this method with the number 23 we get:23/2 = 11 remainder 111/2 = 5 remainder 15/2 = 2 remainder 12/2 = 1 remainder 01/2 = 0 remainder 1So the binary equivalent is 10111
It is C