0
Use the product rule.
y = x lnx
y' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln x
Use the product rule.
y = x lnx
y' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln x
Use the product rule.
y = x lnx
y' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln x
Use the product rule.
y = x lnx
y' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln x
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What is Y double-prime plus y equals 0?
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
Find the derivative of y equals 3cosx?
y=3 cos(x) y' = -3 sin(x)
What is the derivative of y equals sin times x to the power of 2?
D(y)= sin 2x
What is the derivative of y equals sec x?
sec(x)tan(x)
The derivative of y equals e 9x?
If dy/dx = (e) (9x) then Y = 4.5ex2 plus (any constant).==================================The above answer explains how to get the integral of e9x.If you were interested in how to get the derivative of e9x, the answer is e9.I suspect you may have actually wanted to ask how to get the derivative of e9x.In that case, the derivative of e9x is 9e9x.
