0
Use the product rule.
y = x lnx
y' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln x
Use the product rule.
y = x lnx
y' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln x
Use the product rule.
y = x lnx
y' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln x
Use the product rule.
y = x lnx
y' = x (ln x)' + x' (ln x) = x (1/x) + 1 ln x = 1 + ln x
What else can I help you with?
What is Y double-prime plus y equals 0?
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
Find the derivative of y equals 3cosx?
y=3 cos(x) y' = -3 sin(x)
What is the derivative of y equals sin times x to the power of 2?
D(y)= sin 2x
What is the derivative of y equals sec x?
sec(x)tan(x)
The derivative of y equals e 9x?
If dy/dx = (e) (9x) then Y = 4.5ex2 plus (any constant).==================================The above answer explains how to get the integral of e9x.If you were interested in how to get the derivative of e9x, the answer is e9.I suspect you may have actually wanted to ask how to get the derivative of e9x.In that case, the derivative of e9x is 9e9x.
What is the derivative of y equals xln x?
(xlnx)' = lnx + 1
How do you find the mean of x over y equals a over b?
Find the derivative of Y and then divide that by the derivative of A
What is the derivative of 40xy where x equals 2 and y equals 2?
- the derivative with respect to x is 40y - The derivative with respect to Y is 40xSo, since both x and y equal 2, both derivatives yield 40*2 = 80
What is the derivative of lnlnx?
1/xlnx Use the chain rule: ln(ln(x)) The derivative of the outside is1/ln(x) times the derivative of the inside. 1/[x*ln(x)]
What is Y double-prime plus y equals 0?
y"+y'=0 is a differential equation and mean the first derivative plus the second derivative =0.Look at e-x the first derivative is -e-xThe second derivative will be e-xThe sum will be 0
What is the derivative of y equals 2x TIMES 2x?
y=(2x)2 y=2(2x) y=4x
What is the derivative of y equals aex plus be2x plus ce3x with respect to x?
if y=aex+be2x+ce3x then its derivative dy/dx or y' is: y'=aex+2be2x+3ce3x
Why was the calculus student confused about y equals ex and the derivative of y equals ex?
Because the derivative of e^x is e^x (the original function back again). This is the only function that has this behavior.
Find the derivative of y equals 3cosx?
y=3 cos(x) y' = -3 sin(x)
What is the derivative of y equals 36cotx?
Y = 36cot(x)Y' = dy/dx36cot(x)= - 36csc2(x)==========
What is the derivative of y equals sin times x to the power of 2?
D(y)= sin 2x
What is the derivative of y equals sec x?
sec(x)tan(x)
