If the discriminant of a quadratic equation is zero then it has two identical roots.
The discriminant in the quadratic equation x2 + 11x + 121 = x + 96 is 0.Simplify the equation to the form Ax2 + Bx + C = 0 and you get x2 + 10x + 25 = 0. The discriminant is B2 - 4AC or 100 - (4)(1)(25) or 100 - 100 or 0.Not asked, but answered for completeness - since the discriminant is 0, there is one real solution, namely x = (-10 +/- 00.5) / 2 = -5
The discriminant is 25.
The equation is equivalent to: -3x2 - 12x - 1 = 0 [you could change signs to get 3x2 + 12x + 1 = 0 but that is not required] The discriminant is (-12)2 - 4*(-3)(-1) = 144 - 12 = 132
This quadratic equation has no real roots because its discriminant is less than zero.
The discriminant is -11.
If you mean b^2 -4ac then it is the discriminant of a quadratic equation. If the discriminant equals 0 then the equation has 2 equal roots. If the discriminant is greater than 0 then the equation has 2 different roots. If the discriminant is less than 0 then it has no real roots.
The discriminant is 9.
The discriminant is 0.
The discriminant is 36 which means the quadratic equation has two solutions which are 5 and -1
It is: 25-4(8*6) = -167
If the discriminant of a quadratic equation is zero then it has two identical roots.
General form of a quadratic equation is: ax2+b+c = 0 The discriminant is: b2-4ac If the discriminant equals zero then there are two equal roots If the discriminant is greater than zero then there are two different roots If the discriminant is less than zero then there are no real roots
The discriminant is 0.
The discriminant is -439 and so there are no real solutions.
If the discriminant of a quadratic equation is less then 0 then it will have no real solutions.
This quadratic equation has no solutions because the discriminant is less than zero.