Distance formula: square root of (x1-x2)2+(y1-y2)2
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If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
Using the distance formula from (3, 1) to (7, 1) is 4 units
We use the distance formula to find the distance between the points (2,3) and (3,0) The distance is Square root of ((3^2+(2-3)^2)= Square root of (9+1) Which is square root of 10. This is the distance. This works because if we draw a triangle with one side having length 3 and another side having length 1, we have a right triangle. THis is because the side of length 3 is vertical and the side of length 1 is horizontal. Now the hypotenuse of this triangle is the line between the two points in question. So the length of the hypotenuse is the distance between the points. However, the pythagorean theorem tells us this distance is the square root of 1^2 +3^2=Square root of 10
The distance between points: (9, 4) and (3, 4) is 6
The distance between the points is two times the square root of 3.
(3-1)2 + (5-8)2 = 13 and the square root of this is the distance between the points
7.2111 (rounded)
Points: (-4, 3) and (3, -1) Distance: (3--4)2+(-1-3)2 = 65 and the square root if this is the distance which is just over 8
Points: (1, -2) and (1, -5) Distance: 3 units by using the distance formula
If you mean points of (-3, 1) and (-7, 1) then using the distance formula it is 10 units
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If you mean points of: (-5, 1) and (-2, 3) then the distance is about 3.61 rounded to two decimal places
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
what is the distance between the points (-3, -3) and (6, -1)
If you mean points of (1, -2) and (-9, 3) then the distance is about 11 units using the distance formula
The distance between the points of (4, 3) and (0, 3) is 4 units