We use the distance formula to find the distance between the points (2,3) and (3,0) The distance is Square root of ((3^2+(2-3)^2)= Square root of (9+1) Which is square root of 10. This is the distance. This works because if we draw a triangle with one side having length 3 and another side having length 1, we have a right triangle. THis is because the side of length 3 is vertical and the side of length 1 is horizontal. Now the hypotenuse of this triangle is the line between the two points in question. So the length of the hypotenuse is the distance between the points. However, the pythagorean theorem tells us this distance is the square root of 1^2 +3^2=Square root of 10
0 isn't a real number. Distance: the extent or amount of space between two things, points or lines. 0 is not a amount as it is not a number and is the "Distance" were to be 0 then it wouldn't be any leanth away.
1
Pythagoras can be used to find the distance between any two points (x0, y0) and (x1, y1): Distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((5 - 5)² + (13 - 9)²) = √(0 + 4²) = √(4²) = 4.
The distance between the points of (4, 3) and (0, 3) is 4 units
the first point is x = 28 and y = -17. The second point is x = -15 and y = -17. Since both points have the same y coordinate then the points are on a straight horizontal line and distance is the difference of the x coordinates, or 28 - (-15) = 43
5 is.
The distance between the points of (4, 3) and (0, 3) is 4 units
Points: (2, 4) and (5, 0) Distance: 5
Distance between (0,0) and (8,2): √((8-0)2+(2-0)2) = √(82+22) = √(64+4) = √(68) = 2√17 ~= 8.246
The square root of (2x2)+(5x5) is 5.385164807134504 ' . . . . . . .
0 isn't a real number. Distance: the extent or amount of space between two things, points or lines. 0 is not a amount as it is not a number and is the "Distance" were to be 0 then it wouldn't be any leanth away.
1
7
The distance between the points of (2, 3) and (7, 0) is the square root of 34
0 0
Answer: 1
Since they are the same point, the distance between them is 0.